Lecture-Inelastic Collisions.notebook

Transcription

Lecture-Inelastic Collisions.notebook
Lecture­Inelastic Collisions.notebook
November 25, 2012
Happy Ball/Sad Ball Demo:
Click me!
(Do demo while students copy down definitions on next page)
Lecture­Inelastic Collisions.notebook
November 25, 2012
Up until now, we have been pushing objects apart. If
we bring objects together, we call that a collision. We
have two types of collisions:
Lecture­Inelastic Collisions.notebook
November 25, 2012
Up until now, we have been pushing objects apart. If
we bring objects together, we call that a collision. We
have two types of collisions:
Elastic Collision: When objects collide without permanently deforming and without generating heat.
The Result: THEY BOUNCE!!!
Lecture­Inelastic Collisions.notebook
November 25, 2012
Up until now, we have been pushing objects apart. If
we bring objects together, we call that a collision. We
have two types of collisions:
Elastic Collision: When objects collide without permanently deforming and without generating heat.
The Result: THEY BOUNCE!!!
Inelastic Collision: When objects collide, they distort (get tangled together), and generate heat.
The Result: THEY STICK TOGETHER!!!
Lecture­Inelastic Collisions.notebook
In both types of collisions...
November 25, 2012
Lecture­Inelastic Collisions.notebook
November 25, 2012
In both types of collisions...
MOMENTUM IS CONSERVED!!!
Lecture­Inelastic Collisions.notebook
November 25, 2012
In both types of collisions...
MOMENTUM IS CONSERVED!!!
MOMENTUM IS CONSERVED!!!
Lecture­Inelastic Collisions.notebook
November 25, 2012
In both types of collisions...
MOMENTUM IS CONSERVED!!!
MOMENTUM IS CONSERVED!!!
MOMENTUM IS CONSERVED!!!
Lecture­Inelastic Collisions.notebook
IT IS
November 25, 2012
THE
LAW!!!
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
p1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Since p1,2 has double the mass of p1, what can we say about its velocity?
p1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Since p1,2 has double the mass of p1, what can we say about its velocity?
p1,2
The velocity of p1,2 is half of p1, so: v1,2 = 0.5 m /s.
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
mv1 = 2mv1,2
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
mv1 = 2mv1,2
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
mv1 = 2mv1,2
v1 = 2v1,2
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
mv1 = 2mv1,2
v1 = 2v1,2
v1 = v1,2
2
Lecture­Inelastic Collisions.notebook
November 25, 2012
The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together?
p1 = p1,2
(Momentum before = Momentum after)
Here is how we solve with equations and numbers:
p1 = mv1
p1,2
p1,2 = (m + m)v1,2 = 2mv1,2
p1
mv1 = 2mv1,2
v1 = 2v1,2
v1 = v1,2
2
1 m /s
= 0.5 m /s
2
Lecture­Inelastic Collisions.notebook
November 25, 2012
Inelastic Collisions:
2 objects collide and stick together:
p1 + p 2 = p 1+2
Before
Collision
After
Collision
m1 v1 + m 2 v2 = (m 1 + m 2 )v
Remember: Velocity is a Vector!!!
Lecture­Inelastic Collisions.notebook
November 25, 2012
Senteo TIME!!!
Title Page
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
B C D A
1
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
+
Lecture­Inelastic Collisions.notebook
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
November 25, 2012
+
Hint: Momentum before = Momentum After
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
pbefore = p1 + p2
p1 = m1 v1
p2 = m2 v2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
pbefore = p1 + p2
p1 = m1 v1
p1 = (10kg)(400 m /s)
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
p2 = m2 v2
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
pbefore = p1 + p2
p1 = m1 v1
p1 = (10kg)(400 m /s)
p1 = 4,000 a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
kg*m
/s
p2 = m2 v2
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
+
pbefore = p1 + p2
p1 = m1 v1
p1 = (10kg)(400 m /s)
p1 = 4,000 a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
kg*m
/s
p2 = m2 v2
p2 = (200kg)(­25 m /s)
He moves left (negative direction).
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
+
pbefore = p1 + p2
p1 = m1 v1
p1 = (10kg)(400 m /s)
p1 = 4,000 a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
kg*m
/s
p2 = m2 v2
p2 = (200kg)(­25 m /s)
p2 = ­5,000 kg*m /s
He moves left (negative direction).
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
BEFORE:
+
pbefore = p1 + p2 = 4,000 kg*m /s ­ 5,000 kg*m /s = ­1,000 kg*m /s
p1 = m1 v1
p1 = (10kg)(400 m /s)
p1 = 4,000 a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
kg*m
/s
p2 = m2 v2
p2 = (200kg)(­25 m /s)
p2 = ­5,000 kg*m /s
He moves left (negative direction).
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pbefore = pafter +
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
pbefore = pafter pafter a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pafter = (210 kg)v1,2
+
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
+
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pafter = (210 kg)v1,2 = ­1,000 kg*m /s
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
+
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pafter = (210 kg)v1,2 = ­1,000 kg*m /s
(210 kg)
(210 kg)
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
+
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pafter = (210 kg)v1,2 = ­1,000 kg*m /s
(210 kg)
(210 kg)
Lecture­Inelastic Collisions.notebook
November 25, 2012
Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction?
AFTER:
pbefore = ­1,000 kg*m /s
+
pbefore = pafter pafter pafter = (m1 + m2 )v1,2
pafter = (10 kg + 200 kg)v1,2
a) 4.76 m /s right
b) 4.76 m /s left
c) 42.86 m /s right
d) 42.86 m /s left
pafter = (210 kg)v1,2 = ­1,000 kg*m /s
(210 kg)
(210 kg)
v1,2 = ­4.76 m /s so 4.76 m /s left
Lecture­Inelastic Collisions.notebook
November 25, 2012
Duff Man says:
"That's Enough!!!"

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