Matrices and Linear Systems

Transcription

Matrices and Linear Systems
Matrices and Linear Systems


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Roughly speaking, matrix is a rectangle array
We shall discuss existence and uniqueness of
solution for a system of linear equation.
The method of Gauss ellimination will be given to
solve the system .
Advanced Engineering Mathematics by
Erwin Kreyszig
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the row reduced echelon form
1 2 / 3 1 / 3
1 0 1 
0
  0 1  1
1

1




0
0 0 0 
0
0 
Advanced Engineering Mathematics by Erwin Kreyszig
Copyright  2007 John Wiley & Sons, Inc. All rights reserved.
1 3 0 5  1
Example : 
is a row reduced echolon matrix.

0 0 1 0 2 
1. Find row reduced echelon forms of
 1 4
0 0

 0 0
2. Show
1 1
 2 1 3
0 0 ,  0 1 1
 2 0 1
0 1
that they are inconsistent systems.
2x 1   3 x 2
1
2x 1  3 x 2
6
x1 
3x 2
0
4x 1  6x 2
 18
x1 
4x 2
3
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Advanced Engineering Mathematics by
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Vector Spaces

A quantity such as work, area or energy which is
described in terms of magnitude alone is called a scalar.

A quantity which has both magnitude and direction for
its describtion is called a vector.
A vector is an element of vector space.
Advanced Engineering Mathematics by
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Definiton: A vector space V in R is the set satisfying
1.If u , v  V and a  R, then u  v, au  V .
2. u  v  v  u
3. u  (v  w)  (u  v)  w
4. u  0  u (a unique zero element)
5. u  (u )  0 (a uique additive inverse)
6. (a  b)u  au  bu
7.(ab)u  a(bu )
8.1u  u (1 is identity scalar)
9.a(u  v)  au  av
Advanced Engineering Mathematics by
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Examples for vector spaces
1. V  {0}
2. R n
3. R mxn (space of matrices)
4. Pn [x] (space of polynomials)
5. F[a, b] (function - space on [a, b])
n
6. C [a, b] (continously differentiable func.)
Advanced Engineering Mathematics by
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Linear Dependence
Define a linear combinatio n of nonzero vectors
c1u1  c 2 u 2  ...  c n u n ,
where u i  V , ci  R, i  1,2,3,...
If the equation c1u1  c 2 u 2  ...c n u n  0
has only trivial solution for all ci , then
u1 , u 2 ,...u n are linealy independent.Otherwise,
if any ci is zero then they are linearly dependent.
Advanced Engineering Mathematics by
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Rank of A is 2 because the first two rows are linearly independent.
Advanced Engineering Mathematics by
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Example
 2 1 3
1 0 0
A   0 1 1 is row equivalent to 0 1 0.
 2 0 1
0 0 1
rankA  3
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Dimension of a vector space V
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SpanS= All linear combinations of vectors of the subset
S of V .
A basis for V is a linearly independent subset S of V
which spans the space V.
That is, SpanS= V where S is lin. İndep.
dimV= The number of vectors in any basis for V.
V is finite-dimensional if V has a basis consisting of a
finite number of vectors.
Advanced Engineering Mathematics by
Erwin Kreyszig
Note: (6) is known as dimension theorem
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Example
3x1  2 x 2  3x3  2 x 4  1
x1  x 2  x3  0 x 4  3
x1  2 x 2  x3  x 4  2
x0  1 2 0 3 , x h  c 1 0 1 0
T
Advanced Engineering Mathematics by
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T
Determinant
Determinant is a function form square
matrices to scalars.
Our efficient computational procedure will be cofactor
expansion.
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Examples
Advanced Engineering Mathematics by
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Linear Transformations
Examples: Zero transform, identity operator, scalar-multiple
operator,reflection , projection , rotation, differential
transform, integral transform.
Advanced Engineering Mathematics by
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Representiation Matrix
Advanced Engineering Mathematics by
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Example
Advanced Engineering Mathematics by
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Example:
Find the representiation matrix of
Advanced Engineering Mathematics by
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Range and Null (Kernel) spaces
Let F : V  W be a linear tra nsform.
NullF  {u : F (u )  0, u  V }.
RangeF  {v : v  F (u ), u  V }  W
includes all images vectors.
dim (NullF)  nullityF
dim (RangeF)  rankF
Theorem : rankF  nullityF  dim V.
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