chapter 2 resistive circuits

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CHAPTER 2 RESISTIVE CIRCUITS
Electrical Engineering: Principles and Applications, 6e
Allan R. Hambley
Copyright ©2014 by Pearson Education, Inc.
All rights reserved.
Figure 2.1
Series resistances can be combined into an equivalent resistance.
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Figure 2.2
Parallel resistances can be combined into an equivalent resistance.
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Figure 2.3
Resistive network for Example 2.1.
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Figure 2.4
Resistive networks for Exercise 2.1.
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Figure 2.5
A circuit and its simplified versions. See Example 2.2.
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Figure 2.6 After reducing the circuit to a source and an equivalent resistance, we solve the simplified circuit.
Then, we transfer results back to the original circuit. Notice that the logical flow in solving for currents and
voltages starts from the simplified circuit in (c).
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Figure 2.7
Circuits for Exercise 2.2.
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Figure 2.8
Circuit used to derive the voltage-division principle.
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Figure 2.9
Circuit for Example 2.3.
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Figure 2.10
Circuit used to derive the current-division principle.
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Figure 2.11
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Figure 2.12
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Figure 2.13
The voltage-division principle forms the basis for some position sensors. This figure shows a
transducer that produces an output voltage vo proportional to the rudder angle θ.
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Figure 2.14
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Figure 2.15
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Figure 2.16
other nodes.
The first step in node analysis is to select a reference node and label the voltages at each of the
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Figure 2.17
Assuming that we can determine the node voltages v1 , v2 , and v3 , we can use KVL to determine vx , vy , and vz .
Then using Ohm’s law, we can find the current in each of the resistances. Thus, the key problem is in determining the node
voltages.
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Figure 2.18
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Figure 2.19
Circuit for Exercise 2.6.
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Figure 2.20
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Figure 2.21
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Figure 2.22
Circuit of Example 2.8 with a different choice for the reference node. See Exercise 2.9.
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Figure 2.23
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Figure 2.24
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Figure 2.25 A supernode is formed by drawing a dashed line enclosing several nodes and any elements
connected between them.
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Figure 2.26
Node voltages v1 and v2 and the 10-V source form a closed loop to which KVL can be applied. (This
is the same circuit as that of Figure 2.25.)
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Figure 2.27
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Figure 2.28
Circuit containing a current-controlled current source. See Example 2.10.
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Figure 2.29
Circuit containing a voltage-controlled voltage source. See Example 2.11.
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Figure 2.30
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Figure 2.31
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Figure 2.32
Circuit for illustrating the mesh-current method of circuit analysis.
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Figure 2.33
Two circuits and their mesh-current variables.
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Figure 2.34
Circuit of Example 2.13.
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Figure 2.35
Circuit of Exercise 2.19.
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Figure 2.36
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Figure 2.37
In this circuit, we have i1 = 2 A.
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Figure 2.38
A circuit with a current source common to two meshes.
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Figure 2.39
The circuit for Exercise 2.22.
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Figure 2.40
The circuit for Exercise 2.23.
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Figure 2.41
A circuit with a voltage-controlled current source. See Example 2.15.
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Figure 2.42 A two-terminal circuit consisting of resistances and sources can be replaced by a Thévenin
equivalent circuit.
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Figure 2.43
Thévenin equivalent circuit with open-circuited terminals. The open-circuit voltage voc is equal to the
Thévenin voltage Vt.
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Figure 2.44
Thévenin equivalent circuit with short-circuited terminals. The short-circuit current is isc = Vt/Rt.
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Figure 2.45
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Figure 2.46
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Figure 2.47
resistance.
When the source is zeroed, the resistance seen from the circuit terminals is equal to the Thévenin
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Figure 2.48
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Figure 2.49
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Figure 2.50
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Figure 2.51 The Norton equivalent circuit consists of an independent current source In in parallel with the
Thévenin resistance Rt.
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Figure 2.52
The Norton equivalent circuit with a short circuit across its terminals.
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Figure 2.53
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Figure 2.54
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Figure 2.55 A voltage source in series with a resistance is externally equivalent to a current source in parallel
with the resistance, provided that In = Vt /Rt .
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Figure 2.56
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Figure 2.57
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Figure 2.58
Circuits for analysis of maximum power transfer.
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Figure 2.59
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Figure 2.60
Circuit used to illustrate the superposition principle.
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Figure 2.61
A resistance that obeys Ohm’s law is linear.
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Figure 2.62
Circuit for Example 2.22 and Exercise 2.31.
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Figure 2.63
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Figure 2.64
The Wheatstone bridge. When the Wheatstone bridge is balanced, ig=0 and vab=0.
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Figure 2.65a
Strain measurements using the Wheatstone bridge.
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Figure 2.65b
Strain measurements using the Wheatstone bridge.
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Figure P2.1
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Figure P2.3
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Figure P2.4
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Figure P2.6
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Figure P2.8a and b
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Figure P2.8c
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Figure P2.13
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Figure P2.16
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Figure P2.17
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Figure P2.20
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Figure P2.21
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Figure P2.23
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Figure P2.24
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Figure P2.25
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Figure P2.26
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Figure P2.28
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Figure P2.29
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Figure P2.30
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Figure P2.31
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Figure P2.32
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Figure P2.33
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Figure P2.34
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Figure P2.35
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Figure P2.36
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Figure P2.37
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Figure P2.38
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Figure P2.39
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Figure P2.40
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Figure P2.43
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Figure P2.44
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Figure P2.49
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Figure P2.50
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Figure P2.51
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Figure P2.52
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Figure P2.53
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Figure P2.54
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Figure P2.56
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Figure P2.57
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Figure P2.58
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Figure P2.59
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Figure P2.60
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Figure P2.61
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Figure P2.62
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Figure P2.63
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Figure P2.64
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Figure P2.65
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Figure P2.67
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Figure P2.70
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Figure P2.77
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Figure P2.83
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Figure P2.85
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Figure P2.86
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Figure P2.87
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Figure P2.91
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Figure P2.95
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Figure P2.97
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Figure P2.103
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Figure P2.104
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Table T2.1
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Table T2.1 (continued)
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Figure T2.2
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Figure T2.3
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Figure T2.4
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Figure T2.5
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Figure T2.6
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chapter 2 resistive circuits

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