Math 242 The freecalc project team
Transcription
Math 242 The freecalc project team
Math 242 Sample Lecture The freecalc project team Reference Lectures https://sourceforge.net/projects/freecalculus/ 2016 The freecalc team Sample Lecture 2016 Outline 1 Surfaces Quadric Surfaces The freecalc team Sample Lecture 2016 Outline 1 Surfaces Quadric Surfaces 2 Tangent Planes The freecalc team Sample Lecture 2016 Please view this lecture in full screen mode. Scroll down the slides (in full screen mode) to see a demo of the freecalc graphics and presentation. The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . Explicit form, as a parametric surface: x = g(u, v ) y = h(u, v ) z = f (u, v ) The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . Explicit form, as a parametric surface: x = g(u, v ) y = h(u, v ) z = f (u, v ) A partial case of the parametric surface is the graph surface: x = u z = f (x, y ) =⇒ y = v z = The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . Explicit form, as a parametric surface: x = g(u, v ) y = h(u, v ) z = f (u, v ) A partial case of the parametric surface is the graph surface: x = u z = f (x, y ) =⇒ y = v z = The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . Explicit form, as a parametric surface: x = g(u, v ) y = h(u, v ) z = f (u, v ) A partial case of the parametric surface is the graph surface: x = u z = f (x, y ) =⇒ y = v z = f (u, v ) The freecalc team Sample Lecture 2016 Surfaces A surface S can be given in a number of ways. Implicit form, as a level surface: F (x, y , z) = 0 . Explicit form, as a parametric surface: x = g(u, v ) y = h(u, v ) z = f (u, v ) A partial case of the parametric surface is the graph surface: x = u z = f (x, y ) =⇒ y = v z = f (u, v ) A graph surface z = f (x, y ) can be represented as a level surface: z = f (x, y ) ⇐⇒ F (x, y , z) = 0 The freecalc team for Sample Lecture F (x, y , z) = z − f (x, y ) . 2016 Surfaces Quadric Surfaces Quadratic surfaces The level sets for second degree polynomial functions f (x, y , z) = Ax 2 + By 2 + Cz 2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J. are called quadratic surfaces. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Quadratic surfaces The level sets for second degree polynomial functions f (x, y , z) = Ax 2 + By 2 + Cz 2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J. are called quadratic surfaces. At least one of the second-degree terms is required to be non-zero. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Quadratic surfaces The level sets for second degree polynomial functions f (x, y , z) = Ax 2 + By 2 + Cz 2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J. are called quadratic surfaces. At least one of the second-degree terms is required to be non-zero. The coefficients are allowed to be zero. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D = 0, (A, B, C) 6= (0, 0, 0). The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D = 0, (A, B, C) 6= (0, 0, 0). Ax 2 + By 2 + Iz = 0, (A, B) 6= (0, 0), I 6= 0. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D = 0, (A, B, C) 6= (0, 0, 0). These quadratics posses central symmetry: Ax 2 + By 2 + Iz = 0, (A, B) 6= (0, 0), I 6= 0. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D A(−x)2 + B(−y )2 + C(−z)2 + D = 0, = 0, (A, B, C) 6= (0, 0, 0). These quadratics posses central symmetry: if (x, y , z) belongs to the surface, so does (−x, −y , −z). Ax 2 + By 2 + Iz = 0, (A, B) 6= (0, 0), I 6= 0. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D A(−x)2 + B(−y )2 + C(−z)2 + D = 0, = 0, (A, B, C) 6= (0, 0, 0). These quadratics posses central symmetry: if (x, y , z) belongs to the surface, so does (−x, −y , −z). Ax 2 + By 2 + Iz = 0, (A, B) 6= (0, 0), I 6= 0. These quadratics do not posses central symmetry. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Canonical forms of quadratic surfaces. Through rigid motions (translations and rotations) a quadratic surface can be reduced to one of the two canonical forms. Ax 2 + By 2 + Cz 2 + D A(−x)2 + B(−y )2 + C(−z)2 + D = 0, = 0, (A, B, C) 6= (0, 0, 0). These quadratics posses central symmetry: if (x, y , z) belongs to the surface, so does (−x, −y , −z). Ax 2 + By 2 + Iz = 0, (A, B) 6= (0, 0), I 6= 0. These quadratics do not posses central symmetry. The canonical forms above are in addition split into sub-forms depending on the sign of A, B, C, D, I. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D > 0. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D > 0. Then the surface is the empty set. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D > 0. Then the surface is the empty set. Example: x 2 + 2y 2 + 3z 2 + 4 = 0. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y x 1 2 2x z + 13 y 2 = =1− The freecalc team z2 4 Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= 1 . c2 x 1 2 2x z + 13 y 2 = =1− The freecalc team z2 4 Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = z + 13 y 2 = =1− The freecalc team B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 2 2x 1 , a2 1 . c2 z 2 c z2 4 Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = =1− The freecalc team z2 4 Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = =1− The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: Sample Lecture z2 4. 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = -3 =1− = The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: Sample Lecture z2 4. 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y x Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = -3 2 = 1 − z4 = − 54 The freecalc team Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = -2 =1− = The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = -2 =1− =0 The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y x Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = −1 2 = 1 − z4 = The freecalc team Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y x Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = −1 2 = 1 − z4 = 34 The freecalc team Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =0 =1− = The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =0 =1− =1 The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =1 =1− = The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =1 =1− = 34 The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =2 =1− = The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 =2 =1− =0 The freecalc team z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C > 0, D > 0 Consider the surface C = {(x, y , z)|Ax 2 + By 2 + Cz 2 + D = 0}. Let A > 0, B > 0, C > 0, D < 0. Rescale so D = −1. y Set A = 1 , a2 B= 1 , b2 C= Surface becomes: n 2 2 (x, y , z)| xa + yb + x 1 . c2 z 2 c We illustrate the theory on the 2 example: 12 x 2 + 13 y 2 + z4 = 1. 1 2 2x z + 13 y 2 = =1− z2 4 Rewrite: 12 x 2 + 31 y 2 = 1 − The level curves are: z2 4. None for z < 2 and z > 2. Two points for z = ±2. Ellipses for z ∈ (−2, 2). Figure is called ellipsoid. The freecalc team Sample Lecture 2016 o =1 . Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y x y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y x The level curves z = const are: y x x 2 2 + √y 2 z 2 The freecalc team = = Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x y x x 2 2 + √y 2 z 2 The freecalc team = 0 = 0 Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. y x x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = 0 = 0 = (0, 0, 0) Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. y x x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team 1 = = 1 ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x 2 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team 1 = = 1 ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x 2 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = ±1 = 1 = (±1)2 ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = 2 = ( 2)2 = 4 ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y 4 x x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = 2 2)2 = 4 = ( ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y 4 x x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = 2 = ( ± 2)2 = 4 ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team 3 = = ( 3)2 = 9 ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team 3 = 3)2 = 9 = ( ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = ±3 = ( ± 3)2 = 9 ∈ ellipse Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = z2 = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team = z2 = ±z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y 1 2 The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team x = z2 = ±z = ±2z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z 2 y 4 The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team x = z2 = ±z = ±2z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z y 6 3 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z x The level curves z = const are: A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team x = z2 = ±z = ±2z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along ? . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z y 6 3 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z x The level curves z = const are: A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team x = z2 = ±z = ±2z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along lines . ellipse ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 z Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z y The level curves z = const are: x A point for z = 0. Ellipses for z 6= 0. y For y = 0: x 2 2 x 2 x6 x 2 2 + √y 2 z 2 ⇒ (x, y , z) The freecalc team x = z2 = ±z = ±2z = ±3 = ( ± 3)2 = 9 ⇒ the ellipses are stacked along lines . ellipse ⇒ The figure is a (“two-piece”) cone. ∈ Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: y x y x x 2 2 + √y 2 z= 2 = The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: y x y x x 2 2 + √y 2 z =1 2 =1 = 02 + 1 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: y x y x x 2 2 + √y 2 z =1 2 =1 = 02 + 1 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x The level curves z = const are: Ellipses y 2 x 2 2 + √y 2 x z =1 2 =1 = 02 + 1 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y x x 2 2 + √y 2 z= 1 2 =2 = 1 + ( 1)2 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y √ 2 2 x 2 2 + √y 2 x z= 1 2 =2 = 1 + ( 1)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x The level curves z = const are: Ellipses y √ 2 2 x 2 2 + √y 2 x z =±1 2 =2 = 1 + ( ± 1)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y x x 2 2 + √y 2 z= 2 2 =5 = 1 + ( 2)2 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y √ 2 5 x x 2 2 + √y 2 z= 2 2 =5 = 1 + ( 2)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x The level curves z = const are: Ellipses y √ 2 5 x x 2 2 + √y 2 z =±2 2 =5 = 1 + ( ± 2)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y x x 2 2 + √y 2 z= 3 2 =10 = 1 + ( 3)2 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z The level curves z = const are: Ellipses y x y x x 2 2 + √y 2 √ 2 10 z= 3 2 =10 = 1 + ( 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x The level curves z = const are: Ellipses for all z. y x x 2 2 + √y 2 √ 2 10 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 y x x 2 2 + √y 2 √ 2 10 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x x 2 2 + √y 2 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z2 = 1 2 √ 2 10 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x x 2 2 + √y 2 √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x x 2 2 + √y 2 √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x −z = 0 2 x 2 2 + √y 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along hyperbolas. Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: one-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 1 z y x y x √ 2 10 The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 1 2 x 2 − z 2 = 1 2 x x = 1 2 −z 2 +z 1 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 =10 = 1 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: one-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z + 2 z The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z 2 + 12 2 x 2 − z 2 = 12 2 x x = 12 2 −z 2 +z 1 x 2 = x 2 −z ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z =±3 2 = 1 2 ⇒ (x, y , z) ∈ ellipse x −z = 0 2 + ( ± 3)2 ⇒ ellipses: stacked along hyperbolas. Figure called: one-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z + 4 z The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z 2 + 14 2 x 2 − z 2 = 14 2 x x = 14 2 −z 2 +z 1 x 4 = x 2 −z ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z =±3 2 = 1 4 ⇒ (x, y , z) ∈ ellipse x −z = 0 2 + ( ± 3)2 ⇒ ellipses: stacked along hyperbolas. Figure called: one-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D < 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z + 8 z The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z 2 + 18 2 x 2 − z 2 = 18 2 x x = 18 2 −z 2 +z 1 x 8 = x 2 −z ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z =±3 2 = 1 8 ⇒ (x, y , z) ∈ ellipse x −z = 0 2 + ( ± 3)2 ⇒ ellipses: stacked along hyperbolas. Figure called: one-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z + 0 z y x y x The level curves z = const are: Ellipses for all z. For y = 0: x 2 = z2 + 0 2 x 2 − z 2 = 0 2 x x = 0 2 −z 2 +z 0 x = 2 −z ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 x −z = 0 2 z =±3 2 = 0 + ( ± 3)2 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: cone. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: y x y x x 2 2 + √y 2 z = 2 = The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: y x y x x 2 2 + √y 2 z = 1 2 = 0 = 12 − 1 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: y x y x x 2 2 + √y 2 z = 1 2 = 0 = 12 − 1 ⇒ (x, y , z) = (0, 0, The freecalc team 1) Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x When z = const: Two pts. for z = ±1. Ellipses y x x 2 2 + √y 2 z = ±1 2 = 0 = 12 − 1 ⇒ (x, y , z) = (0, 0, ± 1) The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y x x 2 2 + √y 2 z = 2 = 5 3 16 9 = 5 3 2 −1 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y 8 3 x 2 2 + √y 2 x z = 2 = 5 3 16 9 = 5 3 2 −1 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y 8 3 x 2 2 + √y 2 x z = ± 53 2 5 2 = 16 −1 9 = ± 3 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y x x 2 2 + √y 2 z = 2 = 7 3 40 9 = 7 3 2 −1 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y 4 3 x 2 2 + √y 2 √ 10 x z = 2 = 7 3 40 9 = 7 3 2 −1 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y 4 3 x 2 2 + √y 2 √ 10 x z = ± 73 2 7 2 = 40 −1 9 = ± 3 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y x x 2 2 + √y 2 z = 3 2 =8=( 3)2 − 1 ⇒ (x, y , z) ∈ The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z When z = const: Two pts. for z = ±1. Ellipses y x y √ 4 2 x x 2 2 + √y 2 z = 3 2 =8=( 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. y √ 4 2 x x 2 2 + √y 2 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 y √ 4 2 x x 2 2 + √y 2 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 √ 4 2 x x 2 2 + √y 2 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x x 2 2 + √y 2 When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x x 2 2 + √y 2 When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) z − x2 = 0 x 2 2 + √y 2 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along ? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse The freecalc team ⇒ ellipses: stacked along hyperbolas. Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: two-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 1 z y x y √ 4 2 x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 1 2 2 x z2 − 2 = 1 x = 1 z − 2 x2 + z 1 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = 8 = ( ± 3)2 − 1 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: two-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z − 2 z When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z 2 − 12 2 2 z2 − x2 = 12 = 12 z − x2 x2 + z 1 2 = z − x2 x ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z = ±3 2 = ( ± 3)2 − ⇒ (x, y , z) ∈ ellipse 1 2 z − x2 = 0 ⇒ ellipses: stacked along hyperbolas. Figure called: two-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z − 4 z When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z 2 − 14 2 2 z2 − x2 = 14 = 14 z − x2 x2 + z 1 4 = z − x2 x ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z = ±3 2 = ( ± 3)2 − ⇒ (x, y , z) ∈ ellipse 1 4 z − x2 = 0 ⇒ ellipses: stacked along hyperbolas. Figure called: two-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D > 0 Consider the surface n o y2 x2 1 2 C = (x, y , z)| 4 + 2 = z − 8 z When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z 2 − 18 2 2 z2 − x2 = 18 = 18 z − x2 x2 + z 1 8 = z − x2 x ( 2 +z ) y x y x x +z = 0 2 x 2 2 + √y 2 z = ±3 2 = ( ± 3)2 − ⇒ (x, y , z) ∈ ellipse 1 8 z − x2 = 0 ⇒ ellipses: stacked along hyperbolas. Figure called: two-sheet hyperboloid. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Cz 2 + D = 0, A > 0, B > 0, C < 0, D = 0 Consider the surface n o y2 x2 2 C = (x, y , z)| 4 + 2 = z − 0 z y x y x When z = const: Two pts. for z = ±1. Ellipses for |z| > 1. When y = 0: x 2 = z2 − 0 2 2 x z2 − 2 = 0 x = 0 z − 2 x2 + z 0 = z − x2 ( x2 +z ) x +z = 0 2 x 2 2 + √y 2 z − x2 = 0 z = ±3 2 = ( ± 3)2 − 0 ⇒ (x, y , z) ∈ ellipse ⇒ ellipses: stacked along hyperbolas. Figure called: cone. The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y =z x x The freecalc team Sample Lecture 2016 o Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: x x 2 2 + √y 2 z= 2 = The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: x x 2 2 + √y 2 z =0 2 =0 The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: x x 2 2 + √y 2 z =0 2 =0 The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =0 2 =0 (x, y , z) =(0, 0, 0) The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =1 2 =1 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =1 2 =1 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; 2 x x 2 2 + √y 2 z =1 2 =1 ⇒ (x, y , z) ∈ellipse The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =2 2 =2 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =2 2 =2 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; √ 8 x x 2 2 + √y 2 z =2 2 =2 ⇒ (x, y , z) ∈ellipse The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =3 2 =3 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; x x 2 2 + √y 2 z =3 2 =3 ⇒ (x, y , z) ∈ The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z The level curves z = const are: a point for z = 0; ellipses for z > 0. √ 12 x x 2 2 + √y 2 z =3 2 =3 ⇒ (x, y , z) ∈ellipse The freecalc team o Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + √y 2 z =3 2 =3 ⇒ ellipses: stacked along ? ⇒ (x, y , z) ∈ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + √y 2 z =3 2 =3 ⇒ ellipses: stacked along parabola. ⇒ (x, y , z) ∈ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + √y 2 z =3 2 =3 ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. ⇒ (x, y , z) ∈ellipse The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y2 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + √y 2 z =3 2 =3 ⇒ (x, y , z) ∈ellipse The freecalc team ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. What happens if we decrease B? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y4 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + z =3 2 =3 2 y ⇒ (x, y , z) ∈ellipse The freecalc team ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. What happens if we decrease B? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 2 C = (x, y , z)| x4 + y8 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + √y 8 z =3 2 =3 ⇒ (x, y , z) ∈ellipse The freecalc team ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. What happens if we decrease B? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface n 2 y2 C = (x, y , z)| x4 + 64 y x =z o The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + z =3 2 =3 8 y ⇒ (x, y , z) ∈ellipse The freecalc team ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. What happens if we decrease B? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B > 0, I 6= 0 z Consider the surface o n 2 y2 =z C = (x, y , z)| x4 + ”∞” y x The level curves z = const are: a point for z = 0; ellipses for z > 0. x 2 For y = 0: = z 2 z √ 12 x x x 2 2 + z =3 2 =3 ”∞” y ⇒ (x, y , z) ∈ellipse The freecalc team ⇒ ellipses: stacked along parabola. Surface name: paraboloid. If A 6= B: elliptic paraboloid. What happens if we decrease B? Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z A = 13 , |B| = y 1 4 , I = −1. x x z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y =0 y x2 3 x parab. − 0 =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z y 0 , I = −1. A = 13 , |B| = 41 x Set: y =0 x2 3 x parab. − 0 =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = 1 y x2 3 x − ( 1)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z y − 41 , I = −1. A = 13 , |B| = 41 x Set: y = 1 x2 3 x − ( 1)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z y − 41 , I = −1. A = 13 , |B| = 41 x Set: y = ± 1 x2 3 x − (±1)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = 2 y x2 3 x − ( 2)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = 2 y 2 −1 = − 24 x x2 3 − ( 2)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 2 y 2 −1 = − 24 x x2 3 − (±2)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = 3 y x2 3 x − ( 3)2 4 parab. =z z Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 z x2 3 − ( 3)2 4 parab. =z y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 z x2 3 − (±3)2 4 parab. =z y o =z . y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 parab. =z Set: x =0 Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . 0− y2 4 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 parab. =z Set: x =0 Surface: C= n 2 (x, y , z)|x3 − y2 4 0 o =z . y 0− y2 4 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 Set: x = Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . ( 1)2 3 − y2 4 parab. =z 1 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 Set: x = Surface: C= n 2 (x, y , z)|x3 − y2 4 1 3 o =z . y ( 1)2 3 − y2 4 parab. =z 1 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 parab. =z Set: x = ± 1 Surface: C= n 2 (x, y , z)|x3 − y2 4 1 3 o =z . y (±1)2 3 − y2 4 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 Set: x = Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . ( 2)2 3 − y2 4 parab. =z 2 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − 2 − 94 = − 34 z y o =z . − (±3)2 4 ( 2)2 3 − y2 4 parab. =z Set: x = 4 = 22 3 3 y2 4 x2 3 2 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − 2 − 94 = − 34 z 4 y o =z . − (±3)2 4 parab. =z Set: x = ± 2 4 = 22 3 3 y2 x2 3 (±2)2 3 − y2 4 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x 2 − 94 = − 34 z x2 3 − (±3)2 4 Set: x = Surface: C= n 2 (x, y , z)|x3 − y2 4 y o =z . ( 3)2 3 − y2 4 parab. =z 3 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 y o =z . x2 3 − (±3)2 4 Set: x = ( 3)2 3 − y2 4 parab. =z 3 parab. =z y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 y o =z . x2 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 − y2 4 parab. =z Set: z =2 y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 y o =z . x2 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 − y2 4 parab. =z Set: z =2 2 − y4 =2 x2 3 y x The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 (±3)2 4 parab. =z Set: x = ± 3 − y2 4 parab. =z Set: z =2 y x The freecalc team − (±3)2 3 y o =z . x2 3 √x − 3 Sample Lecture y2 x2 3 − 4 =2 y √x + y =2 2 2 3 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =2 y x √x − 3 y2 x2 3 − 4 =2 y √x + y 2 2 =2 3 √x − y = x 2 2 3 √ + 3 The freecalc team Sample Lecture y 2 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =2 y x √x − 3 y2 x2 3 − 4 =2 y √x + y 2 2 =2 3 √x − y = x 2 2 3 √ + 3 y 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 =2 y √x + y 2 2 =2 3 √x − y = x 2 2 3 √ + 3 y 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 =2 y √x + y 2 2 =2 3 √x − y = x 2 2 3 √ + 3 y 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 hyperb. Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 =2 y √x + y 2 2 =2 3 √x − y = x 2 2 3 √ + 3 y 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 hyperb. Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =1 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 =1 y √x + y 2 2 =1 3 √x − y = x 1 2 3 √ + 3 y 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 hyperb. Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z =0 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 =0 y √x + y =0 2 2 3 two lines x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z = − 1 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 = − 1 y √x + y 2 2=−1 3 √x − y = x −1 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n 2 (x, y , z)|x3 − y2 4 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y o =z . x2 3 − y2 4 parab. =z Set: z = − 2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 = − 2 y √x + y 2 2=−2 3 √x − y = x −2 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n o 2 2 (x, y , z)|x3 − y4 = z . Name: hyperbolic paraboloid. 2 − 94 = − 34 2 z 3 3= 3 x2 3 − (±3)2 4 Set: x = ± 3 (±3)2 3 y parab. =z − y2 4 parab. =z Set: z = − 2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 = − 2 y √x + y 2 2=−2 3 √x − y = x −2 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n o 2 2 (x, y , z)|x3 − y4 = z . Name: hyperbolic paraboloid. 2 − 94 = − 34 2 z 3 3= 3 x2 3 − (±3)2 4 Set: x = ± 3 (±3)2 3 y parab. =z − y2 4 parab. =z Set: z = − 2 x + y = 0 √ 2 3 y x √x − 3 y2 x2 3 − 4 = − 2 y √x + y 2 2=−2 3 √x − y = x −2 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n o 2 2 (x, y , z)|x3 − y4 = z . Name: hyperbolic paraboloid. 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y − y2 4 parab. =z Set: z = − 2 x + y = 0 √ 2 3 y What happens if |B| decreases? x2 3 x √x − 3 y2 x2 3 − 4 = − 2 y √x + y 2 2=−2 3 √x − y = x −2 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z A = 13 , |B| = y x x 2 − 98 = − 38 z Surface: C= n o 2 2 (x, y , z)|x3 − y8 = z . Name: hyperbolic paraboloid. 2 3 = 33 What happens if |B| decreases? − , I = −1. Set: y = ± 3 (±3)2 8 parab. =z Set: x = ± 3 y y x + √ √ =0 3 y8 x2 3 1 8 (±3)2 3 − y2 8 parab. =z Set: z = − 2 y2 x2 3 − 8 = − 2 √x − √y √x + √y =−2 3 8 3 8 x √x − √y = x −2 y 3 8 √ +√ 3 8 y x − √ √ =0 8 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z 1 , I = −1. A = 13 , |B| = 16 x Set: y = ±3 2 y x 9 = −3 − 16 16 z Surface: C= n o 2 y2 (x, y , z)|x3 − 16 =z . Name: hyperbolic paraboloid. 2 3 = 33 − (±3)2 16 parab. =z Set: x = ± 3 (±3)2 3 y − y2 16 parab. =z Set: z = − 2 x + y = 0 √ 4 3 y What happens if |B| decreases? x2 3 x √x − 3 y2 x2 3 − 16 = − 2 y √x + y 4 4=−2 3 √x − y = x −2 y 4 3 √ + 3 4 x − y = 0 √ 4 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z 1 A = 13 , |B| = ∞ = 0, I = −1. x Set: y = ± 3 y 0 x2 3 x z Surface: C= n o 2 (x, y , z)|x3 − 0 = z . Name: hyperbolic paraboloid. 2 3 = 33 parab. Set: x = ± 3 y (±3)2 3 − 0 =z parab. Set: z = − 2 x2 3 −0=−2 x +0 = 0 √ 3 y What happens if |B| decreases? 0 =z − x x −0 = 0 √ 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Ax 2 + By 2 + Iz = 0, A > 0, B < 0, C = 0, I 6= 0 z z , I = −1. A = 13 , |B| = 41 x Set: y = ± 3 y x Surface: C= n o 2 2 (x, y , z)|x3 − y4 = z . Name: hyperbolic paraboloid. 2 − 94 = − 34 2 z 3 3= 3 − (±3)2 4 parab. =z Set: x = ± 3 (±3)2 3 y − y2 4 parab. =z Set: z = − 2 x + y = 0 √ 2 3 y What happens if |B| decreases? x2 3 x √x − 3 y2 x2 3 − 4 = − 2 y √x + y 2 2=−2 3 √x − y = x −2 y 2 3 √ + 3 2 x − y = 0 √ 2 3 The freecalc team Sample Lecture 2016 Surfaces Quadric Surfaces Summary: surfaces of form Ax 2 + By 2 + Cz 2 + D = 0 A B C >0 >0 >0 >0 >0 >0 >0 >0 >0 >0 >0 =0 >0 >0 =0 >0 >0 =0 >0 >0 <0 >0 >0 <0 >0 >0 <0 >0 =0 =0 >0 =0 =0 >0 =0 =0 Fill in the rest of the table. The freecalc team D >0 =0 <0 >0 =0 <0 >0 =0 <0 >0 =0 <0 x = x0 empty y = y0 empty z = z0 empty Example x 2 + 2y 2 + 3z 2 + 4 = 0 Name empty ellipse ellipse ellipse x 2 + 2y 2 + 3z 2 − 4 = 0 Ellipsoid Sample Lecture 2016 Surfaces Quadric Surfaces Quadratics Ax 2 + By 2 + Iz = 0 (no central symmetry) Ax 2 + By 2 + Iz = 0 A B x = x0 >0 >0 parabola >0 =0 >0 <0 Fill in the rest of the table. The freecalc team y = y0 parabola z = z0 ellipse, point, or empty Sample Lecture Example x 2 + 2y 2 + 3z = 0 Name Elliptic paraboloid 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. How should we define the notion of “a plane tangent to S at P” so that it matches our geometric intuition? The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. How should we define the notion of “a plane tangent to S at P” so that it matches our geometric intuition? Intuitively, it should include all tangents at P to curves passing through P and contained in the surface. The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. How should we define the notion of “a plane tangent to S at P” so that it matches our geometric intuition? Intuitively, it should include all tangents at P to curves passing through P and contained in the surface. The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. How should we define the notion of “a plane tangent to S at P” so that it matches our geometric intuition? Intuitively, it should include all tangents at P to curves passing through P and contained in the surface. The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane Consider a surface S in space and a point P on the surface. How should we define the notion of “a plane tangent to S at P” so that it matches our geometric intuition? Intuitively, it should include all tangents at P to curves passing through P and contained in the surface. Therefore it should be the plane The freecalc team passing through P; parallel to the directions of all tangent vectors of curves passing through P and contained in the surface. Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z y Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. x The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z y Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; x The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z y x The freecalc team Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) The freecalc team Sample Lecture . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) The freecalc team p0 (x0 ) Sample Lecture = (1, 0, fx (x0 , y0 )) . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) The freecalc team p0 (x0 ) Sample Lecture = (1, 0, fx (x0 , y0 )) . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) The freecalc team p0 (x0 ) q0 (y0 ) Sample Lecture = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = . The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) The freecalc team Sample Lecture . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) The freecalc team Sample Lecture . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = The freecalc team Sample Lecture . 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . Equation of tangent plane at P(x0 , y0 , f (x0 , y0 )): n · (r − r0 ) = 0 The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . Equation of tangent plane at P(x0 , y0 , f (x0 , y0 )): n · (r − r0 ) = 0 − fx (x0 , y0 )(x − x0 ) − fy (x0 , y0 )(y − y0 ) + (z − f (x0 , y0 )) = 0 The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . Equation of tangent plane at P(x0 , y0 , f (x0 , y0 )): n · (r − r0 ) = 0 − fx (x0 , y0 )(x − x0 ) − fy (x0 , y0 )(y − y0 ) + (z − f (x0 , y0 )) = 0 The freecalc team Sample Lecture 2016 Tangent Planes Tangent Plane to a Graph Surface z Graph surface z = f (x, y ), point P(x0 , y0 , z0 ) on the surface. y Call p(x) the curve given by f (x, y ) by keeping y = y0 constant; call q(y ) the curve given by f (x, y ) by keeping x = x0 constant. x p(x) q(y ) = (x, y0 , f (x, y0 )) = (x0 , y , f (x0 , y )) p0 (x0 ) q0 (y0 ) = = (1, 0, fx (x0 , y0 )) (0, 1, fy (x0 , y0 )) . Normal to tangent plane at P: n = p0 (x0 ) × q0 (y0 ) = (1, 0, fx (x0 , y0 )) × (0, 1, fy (x0 , y0 )) = (−fx (x0 , y0 ), −fy (x0 , y0 ), 1) . Equation of tangent plane at P(x0 , y0 , f (x0 , y0 )): n · (r − r0 ) = 0 − fx (x0 , y0 )(x − x0 ) − fy (x0 , y0 )(y − y0 ) + (z − f (x0 , y0 )) = 0 z = f (x0 , y0 ) + fx (x0 , y0 )(x − x0 ) + fy (x0 , y0 )(y − y0 ) . The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 ∂f dy ∂f dx = 1, 0, + 0, 1, dt |t=0 ∂x |t=0 dt |t=0 ∂y |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 ∂f dy ∂f dx = 1, 0, + 0, 1, dt |t=0 ∂x |t=0 dt |t=0 ∂y |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 ∂f dy ∂f dx = 1, 0, + 0, 1, dt |t=0 ∂x |t=0 dt |t=0 ∂y |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 ∂f dy ∂f dx = 1, 0, + 0, 1, dt |t=0 ∂x |t=0 dt |t=0 ∂y |t=0 The freecalc team Sample Lecture 2016 Tangent Planes Let z = f (x, y ) be a function and let (x0 , y0 ) be a point such that f is differentiable in a small disk near (x0 , y0 ). The graph of f (x, y ) is the surface S = {(x, y , f (x, y ))}. Let (x, y ) be a point in the domain of f . By the vertical line test there is exactly one point in S whose first two coordinates are x, y . This is the point (x, y , f (x, y )). Let q(t) = (x(t), y (t), z(t)) be a curve lying in S such that x(0) = x0 and y (0) = y0 . By the preceding remarks it follows that z(t) = f (x(t), y (t)). Then the tangent vector of q(t) at t = 0 is dq dx dy d = , , (f (x(t), y (t))) dt |t=0 dt dt dt |t=0 dx dy ∂f dx ∂f dy = , , + dt dt ∂x dt ∂y dt |t=0 ∂f dy ∂f dx = 1, 0, + 0, 1, dt |t=0 ∂x |t=0 dt |t=0 ∂y |t=0 The freecalc team Sample Lecture 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 The freecalc team Sample Lecture dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, z y x (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 at (x0 , y0 , z0 ) was defined as the Recall the tangent space space passing through (x0 , y0 , z0 ) and spanned by the tangents of all curves lying in the surface and passing through (x0 , y0 , z0 ). The freecalc team Sample Lecture 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, z y x (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 at (x0 , y0 , z0 ) was defined as the Recall the tangent space space passing through (x0 , y0 , z0 ) and spanned by the tangents of all curves lying in the surface and passing through (x0 , y0 , z0 ). The freecalc team Sample Lecture 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, z y x (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 Recall the tangent (space) plane at (x0 , y0 , z0 ) was defined as the (space) passing through (x0 , y0 , z0 ) and spanned by the tangents of all curves lying in the surface and passing through (x0 , y0 , z0 ). Corollary (Justification of tangent plane definition) The tangent vector to any curve passing through (x0 , y0 , z0 ) is a linear ∂f ∂f combination of the vectors 1, 0, ∂x and 0, 1, ∂y . In particular the tangent space at (x0 , y0 , z0 ) is a plane. The freecalc team Sample Lecture 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, z y x (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 Recall the tangent (space) plane at (x0 , y0 , z0 ) was defined as the (space) passing through (x0 , y0 , z0 ) and spanned by the tangents of all curves lying in the surface and passing through (x0 , y0 , z0 ). Corollary (Justification of tangent plane definition) The tangent vector to any curve passing through (x0 , y0 , z0 ) is a linear ∂f ∂f combination of the vectors 1, 0, ∂x and 0, 1, ∂y . In particular the tangent space at (x0 , y0 , z0 ) is a plane. The freecalc team Sample Lecture 2016 Tangent Planes q(t) = (x(t), y (t), z(t)) - smooth curve in S = {(x, y , f (x, y ))}, z y x (x0 , y0 , z0 )- point in S, q(0) = (x(0), y (0), z(0)) = (x0 , y0 , z0 ). dq = dt |t=0 dx ∂f 1, 0, dt |t=0 ∂x |t=0 . dy ∂f + 0, 1, dt |t=0 ∂y |t=0 Recall the tangent (space) plane at (x0 , y0 , z0 ) was defined as the (space) passing through (x0 , y0 , z0 ) and spanned by the tangents of all curves lying in the surface and passing through (x0 , y0 , z0 ). Corollary (Justification of tangent plane definition) The tangent vector to any curve passing through (x0 , y0 , z0 ) is a linear ∂f ∂f combination of the vectors 1, 0, ∂x and 0, 1, ∂y . In particular the tangent space at (x0 , y0 , z0 ) is a plane. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. Example: x 2 + y 2 + z 2 = 1: can’t solve for z globally. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. 2 2 2 Example: p x + y + z = 1: can’t solve for z globally. Informally, z = ± 1 − x 2 − y 2 , however this is not a function if we can’t decide on choice of + or −. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. 2 2 2 Example: p x + y + z = 1: can’t solve for z globally. Informally, z = ± 1 − x 2 − y 2 , however this is not a function if we can’t decide on choice of + or −. Locally, with additional requirements, a level surface can be represented as graph surfaces. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. 2 2 2 Example: p x + y + z = 1: can’t solve for z globally. Informally, z = ± 1 − x 2 − y 2 , however this is not a function if we can’t decide on choice of + or −. Locally, with additional requirements, a level surface can be represented as graph surfaces. NearpP(0, 0, 1), the surface is the graph surface of z = 1 − x 2 − y 2. The freecalc team Sample Lecture 2016 Tangent Planes Question Can a given level surface be represented as a graph surface? Globally, level surfaces are cannot be represented as graph surfaces. 2 2 2 Example: p x + y + z = 1: can’t solve for z globally. Informally, z = ± 1 − x 2 − y 2 , however this is not a function if we can’t decide on choice of + or −. Locally, with additional requirements, a level surface can be represented as graph surfaces. NearpP(0, 0, 1), the surface is the graph surface of z = 1 − x 2 − y 2. Near P(1, 0, 0), the surface is not a graph surface w.r.t. to z. The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . We say the level surface is a graph surface around P if there is a function z = f (x, y ) such that: The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . We say the level surface is a graph surface around P if there is a function z = f (x, y ) such that: f is defined on an open disk D around (x0 , y0 ); The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . We say the level surface is a graph surface around P if there is a function z = f (x, y ) such that: f is defined on an open disk D around (x0 , y0 ); f (x0 , y0 ) = z0 ; The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . We say the level surface is a graph surface around P if there is a function z = f (x, y ) such that: f is defined on an open disk D around (x0 , y0 ); f (x0 , y0 ) = z0 ; F (x, y , f (x, y )) = 0 for all (x, y ) in the disk D. The freecalc team Sample Lecture 2016 Tangent Planes Let F (x, y , z)- function, let P(x0 , y0 , z0 ) - point in the domain of F . Let F (x0 , y0 , z0 ) = k . We say the level surface is a graph surface around P if there is a function z = f (x, y ) such that: f is defined on an open disk D around (x0 , y0 ); f (x0 , y0 ) = z0 ; F (x, y , f (x, y )) = 0 for all (x, y ) in the disk D. If the level surface is a graph surface, we say that the equation F (x, y , z) = k implicitly defines z = f (x, y ) satisfying the condition f (x0 , y0 ) = z0 . The freecalc team Sample Lecture 2016