Lecture-Inelastic Collisions.notebook
Transcription
Lecture-Inelastic Collisions.notebook
LectureInelastic Collisions.notebook November 25, 2012 Happy Ball/Sad Ball Demo: Click me! (Do demo while students copy down definitions on next page) LectureInelastic Collisions.notebook November 25, 2012 Up until now, we have been pushing objects apart. If we bring objects together, we call that a collision. We have two types of collisions: LectureInelastic Collisions.notebook November 25, 2012 Up until now, we have been pushing objects apart. If we bring objects together, we call that a collision. We have two types of collisions: Elastic Collision: When objects collide without permanently deforming and without generating heat. The Result: THEY BOUNCE!!! LectureInelastic Collisions.notebook November 25, 2012 Up until now, we have been pushing objects apart. If we bring objects together, we call that a collision. We have two types of collisions: Elastic Collision: When objects collide without permanently deforming and without generating heat. The Result: THEY BOUNCE!!! Inelastic Collision: When objects collide, they distort (get tangled together), and generate heat. The Result: THEY STICK TOGETHER!!! LectureInelastic Collisions.notebook In both types of collisions... November 25, 2012 LectureInelastic Collisions.notebook November 25, 2012 In both types of collisions... MOMENTUM IS CONSERVED!!! LectureInelastic Collisions.notebook November 25, 2012 In both types of collisions... MOMENTUM IS CONSERVED!!! MOMENTUM IS CONSERVED!!! LectureInelastic Collisions.notebook November 25, 2012 In both types of collisions... MOMENTUM IS CONSERVED!!! MOMENTUM IS CONSERVED!!! MOMENTUM IS CONSERVED!!! LectureInelastic Collisions.notebook IT IS November 25, 2012 THE LAW!!! LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) p1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Since p1,2 has double the mass of p1, what can we say about its velocity? p1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Since p1,2 has double the mass of p1, what can we say about its velocity? p1,2 The velocity of p1,2 is half of p1, so: v1,2 = 0.5 m /s. p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 mv1 = 2mv1,2 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 mv1 = 2mv1,2 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 mv1 = 2mv1,2 v1 = 2v1,2 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 mv1 = 2mv1,2 v1 = 2v1,2 v1 = v1,2 2 LectureInelastic Collisions.notebook November 25, 2012 The hoverpuck leaves the rubber band launcher with a velocity of 1 m /s. Shortly after it collides and sticks to a second hoverpuck. If each hoverpuck has a mass of 0.3 kg (and they do!!!), how fast do they travel together? p1 = p1,2 (Momentum before = Momentum after) Here is how we solve with equations and numbers: p1 = mv1 p1,2 p1,2 = (m + m)v1,2 = 2mv1,2 p1 mv1 = 2mv1,2 v1 = 2v1,2 v1 = v1,2 2 1 m /s = 0.5 m /s 2 LectureInelastic Collisions.notebook November 25, 2012 Inelastic Collisions: 2 objects collide and stick together: p1 + p 2 = p 1+2 Before Collision After Collision m1 v1 + m 2 v2 = (m 1 + m 2 )v Remember: Velocity is a Vector!!! LectureInelastic Collisions.notebook November 25, 2012 Senteo TIME!!! Title Page LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? B C D A 1 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left + LectureInelastic Collisions.notebook Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? November 25, 2012 + Hint: Momentum before = Momentum After a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: pbefore = p1 + p2 p1 = m1 v1 p2 = m2 v2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: pbefore = p1 + p2 p1 = m1 v1 p1 = (10kg)(400 m /s) a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left p2 = m2 v2 + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: pbefore = p1 + p2 p1 = m1 v1 p1 = (10kg)(400 m /s) p1 = 4,000 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left kg*m /s p2 = m2 v2 + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: + pbefore = p1 + p2 p1 = m1 v1 p1 = (10kg)(400 m /s) p1 = 4,000 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left kg*m /s p2 = m2 v2 p2 = (200kg)(25 m /s) He moves left (negative direction). LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: + pbefore = p1 + p2 p1 = m1 v1 p1 = (10kg)(400 m /s) p1 = 4,000 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left kg*m /s p2 = m2 v2 p2 = (200kg)(25 m /s) p2 = 5,000 kg*m /s He moves left (negative direction). LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? BEFORE: + pbefore = p1 + p2 = 4,000 kg*m /s 5,000 kg*m /s = 1,000 kg*m /s p1 = m1 v1 p1 = (10kg)(400 m /s) p1 = 4,000 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left kg*m /s p2 = m2 v2 p2 = (200kg)(25 m /s) p2 = 5,000 kg*m /s He moves left (negative direction). LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pbefore = pafter + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s pbefore = pafter pafter a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s pbefore = pafter pafter pafter = (m1 + m2 )v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pafter = (210 kg)v1,2 + LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s + pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pafter = (210 kg)v1,2 = 1,000 kg*m /s LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s + pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pafter = (210 kg)v1,2 = 1,000 kg*m /s (210 kg) (210 kg) LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s + pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pafter = (210 kg)v1,2 = 1,000 kg*m /s (210 kg) (210 kg) LectureInelastic Collisions.notebook November 25, 2012 Radioactive Man (200 kg) flying towards the cannon at 25 m /s catches the 10 kg cannonball (traveling 400 m /s). What is the resulting speed and direction? AFTER: pbefore = 1,000 kg*m /s + pbefore = pafter pafter pafter = (m1 + m2 )v1,2 pafter = (10 kg + 200 kg)v1,2 a) 4.76 m /s right b) 4.76 m /s left c) 42.86 m /s right d) 42.86 m /s left pafter = (210 kg)v1,2 = 1,000 kg*m /s (210 kg) (210 kg) v1,2 = 4.76 m /s so 4.76 m /s left LectureInelastic Collisions.notebook November 25, 2012 Duff Man says: "That's Enough!!!"
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