Civil PE Sample Examination Michael R. Lindeburg, PE Fourth Edition
Transcription
Civil PE Sample Examination Michael R. Lindeburg, PE Fourth Edition
Civil PE Sample Examination Fourth Edition Michael R. Lindeburg, PE Professional Publications, Inc. • Belmont, California 17 Afternoon Session Construction . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . 41. Consider the two cross sections shown. 43. The following table shows unreduced profile leveling readings. h = 12 ft 1 1 2 2 b = 46 ft sta 13+00 g = 13 ft i = 11 ft h = 9 ft BS 3.57 HI FS IFS elevation 617.24 4.29 5.17 2.65 8.21 3.75 The elevation at sta 3+90 is most nearly (A) 609 ft b = 44 ft l = 25 ft station BM 145 1+00 2+00 TP1 3+90 r = 28 ft (B) 610 ft sta 15+00 (C) 612 ft (not to scale) (D) 615 ft Using the average end area method, what is most nearly the volume between sta 13+00 and sta 15+00? (A) 3800 yd3 (B) 4200 yd3 (C) 4600 yd3 44. A foundation contractor bid on constructing the residence shown. The foundation consists of exterior footings totaling 207 linear feet (measuring 16 in 8 in) and four column footings (measuring 3 ft 3 ft 12 in). (D) 5000 yd3 3 ft 42. A planimeter recorded the areas enclosed by the 700 ft and 707 ft grading contours as 1200 ft2 and 1800 ft2, respectively. 3 ft 3 ft 3 ft 3 ft 3 ft basement 3 ft 3 ft garage 707 ft 700 ft The volume of material enclosed by the contour lines is most nearly 3 (A) 4000 ft 3 (B) 11,000 ft (C) 14,000 ft3 (D) 21,000 ft3 Due to poor soil conditions, the area of both the exterior and column footings must be increased by 50%, with no change to footing depths. The additional concrete needed to make the larger footings is most nearly (A) 2.7 yd3 (B) 4.1 yd3 (C) 7.4 yd3 (D) 12 yd3 P P I * w w w . p p i 2 p a s s . c o m 18 C I V I L P E S A M P L E E X A M I N A T I O N 45. Consider the mass diagram shown. The amounts of AC and AB pavement, respectively, from sta 22+00 to sta 32+00 is most nearly (A) 1470 tons and 1110 tons (B) 2560 tons and 1560 tons sta 0+00 sta 6+00 sta 12+00 (C) 3330 tons and 2220 tons (D) 4400 tons and 3330 tons Select the ground profile that best corresponds to the mass diagram. 47. A contractor is bidding on a painting job with the following considerations. . The total area to be painted measures 34,600 ft2. (A) . A five-gallon bucket of paint costs $10. 0+00 12+00 . A five-gallon bucket of paint covers 1200 ft2. . Labor costs $25/hr. . The production rate is 700 ft2/hr. (B) . The overhead cost of labor is 35%. . The overhead cost of materials is 30%. 0+00 12+00 The total bid for the job is most nearly (A) $1850 (B) $1920 (C) (C) $2040 0+00 12+00 (D) $3710 48. A building with 16 bays is to be constructed with the following considerations. (D) 0+00 12+00 . Bay type A will cost $100,000. . Bay type B will cost $85,000. . Bay type C will cost $70,000. 46. Skyline Road is constructed as follows. . The total cost of entrances will be $20,000. . 6 in AC pavement at 110 lbf/yd thickness . An elevator will cost $40,000. 2 per inch of . The total cost of end walls will be $60,000. . 6 in AB pavement at 3000 lbf/yd3 . All equipment will cost $80,000. . pavement width of 40 ft (both lanes) sta 22+00 Skyline Road sta 32+00 P P I * w w w . p p i 2 p a s s . c o m A C C A B A B B B B A B A C C A 81 Solutions Afternoon Session Construction . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . .. . . . .. . . . .. . . . .. . . 41. The cross section at sta 13+00 is known as a onelevel section because the surface is at one elevation at all points. The cross section at sta 15+00 is known as a five-level section because the surface has five different elevation points. Excavation volumes can be calculated using either the average end area method or the prismoidal method. When the cross-section shapes are irregular and largely spaced as they are in this problem, contractors often use the average end area method because it results in a larger calculated volume. (Contractors are generally paid by volume.) Asta 13þ00 ¼ hðsh þ bÞ ¼ ð12 ftÞðð2Þð12 ftÞ þ 46 ftÞ ¼ 840 ft2 The end area at sta 15+00 is þ ð11 ftÞð28 ftÞ 2 2 ¼ 514:5 ft ¼ L ¼ 15þ00 sta 13þ00 sta ¼ 200 ft LðAsta 13þ00 þ Asta 15þ00 Þ V¼ 2 ð200 ftÞð840 ft2 þ 514:5 ft2 Þ ¼ ft3 ð2Þ 27 yd3 The answer is (D). V ¼ ðcontour elevation differenceÞðaverage end areaÞ 1800 ft2 þ 1200 ft2 ¼ ð707 ft 700 ftÞ 2 ¼ 10;500 ft3 ð11;000 ft3 Þ 43. In differential leveling, only one foresight measurement is taken, but in profile leveling, as many intermediate foresight (IFS) measurements as needed are taken. In the elevation calculations, two equations are used. HI ¼ elev þ BS hb þ gl þ ir 2 ð9 ftÞð44 ftÞ þ ð13 ftÞð25 ftÞ ¼ 5017 yd3 The volume of material enclosed between the contour lines is The answer is (B). The end area at sta 13+00 is Asta 15þ00 ¼ 42. Planimeters are mechanical or digital instruments that are used to measure areas enclosed by boundaries such as curved lines, contour lines, and so on. ð5000 yd3 Þ elev ¼ HI FS BS is the backsight, HI is the height of instrument, and FS is the foresight. The instrument is not moved between benchmarks and turning points. Calculate the elevation of each station in series. HIBM 145 ¼ elevBM 145 þ BSBM 145 ¼ 617:24 ft þ 3:57 ft ¼ 620:81 ft elevsta 1þ00 ¼ HI IFSsta 1þ00 ¼ 620:81 ft 4:29 ft ¼ 616:52 ft elevsta 2þ00 ¼ HI IFSsta 2þ00 ¼ 620:81 ft 5:17 ft ¼ 615:64 ft P P I * w w w . p p i 2 p a s s . c o m 82 C I V I L P E S A M P L E E X A M I N A T I O N elevTP1 ¼ HI FSTP1 V footings;column ¼ ¼ 620:81 ft 8:21 ft ¼ 612:60 ft ¼ 2:00 yd3 HITP1 ¼ elevTP1 þ BSTP1 V footings;total constructed ¼ 10:2 yd3 þ 2:00 yd3 ¼ 612:60 ft þ 2:65 ft ¼ 12:2 yd3 ¼ 615:25 ft additional concrete needed ¼ V footings;total constructed elevsta 3þ90 ¼ HI IFSsta 3þ90 V footings;total bid ¼ 615:25 ft 3:75 ft ¼ 12:2 yd3 8:1 yd3 ¼ 611:50 ft ð612 ftÞ station BM 145 1+00 2+00 TP1 3+90 BS 3.57 2.65 HI 620.81 620.81 620.81 615.25 615.25 FS IFS 4.29 5.17 8.21 3.75 ¼ 4:1 yd3 elevation 617.24 616.52 615.64 612.60 611.50 The answer is (C). 44. The bid volume, Vfootings,total bid, is calculated using the following series of calculations. V footing ¼ W footing Dfooting Lfooting ð16 inÞð8 inÞð207 ftÞ V footings;continuous ¼ in 2 ft3 27 12 ft yd3 ¼ 6:8 yd 3 The answer is (B). 45. The mass diagram rises from sta 0+00 to sta 6+00, which means that a portion of the ground profile must be an excavation. Then, the mass diagram curve falls from sta 6+00 to sta 12+00, which means that a portion of the ground profile is an embankment. Peaks occur at a transition from excavation to embankment. The diagram that has these characteristics is option B. The answer is (B). 46. The length of Skyline Road is 32þ00 sta 22þ00 sta ¼ 10 sta ð4Þð3 ftÞð3 ftÞð1 ftÞ ft3 27 yd3 ¼ 1:3 yd3 ð6 inÞ 110 ¼ 8:1 yd3 The actual constructed volume is found similarly. V footings;continuous ¼ ð16 inÞð8 inÞð207 ftÞð1:5Þ in 2 ft3 12 27 ft yd3 ¼ 10:2 yd P P I * AC tonnage ¼ lbf ð1000 ftÞð40 ftÞ yd2 -in 2 ft lbf 3 2000 yd ton ¼ 1467 tons V footings;total bid ¼ 6:8 yd3 þ 1:3 yd3 3 w w w . p p i 2 p a s s . c o m ð1000 ftÞ 110 lbf/yd2 is the given area for a 1 in thick asphalt section of AC pavement, and the asphalt is 6 in thick. V footings;column ¼ ðnumber of footingsÞAfootings D footing ¼ ð4Þð3 ftÞð3 ftÞð1 ftÞð1:5Þ ft3 27 yd3 ð1470 tonsÞ 3000 lbf/yd3 is the given volume for the AB pavement, and the asphalt is 6 in thick. lbf ð1000 ftÞð40 ftÞð6 inÞ 3000 yd3 AB tonnage ¼ in ft3 lbf 12 27 2000 yd3 ft ton ¼ 1111 tons The answer is (A). ð1110 tonsÞ