Lecture 5: Kinematics in 2-3D Physics 218 Alexei Safonov
Transcription
Lecture 5: Kinematics in 2-3D Physics 218 Alexei Safonov
Physics 218 Lecture 5: Kinematics in 2-3D Alexei Safonov Checklist for Today • For the rest of this week: – Be ready for the lab (WebAssign) including pre-labs • Did you get my email about the question on the uncertainty for volume in problem #4? – Quiz at the recitation on Chapter 2 – There was a pre-lecture for today • Many people completed, but not all – A pre-lecture due Wednesday morning • Don’t forget the checkpoints – Homework for Chapter 2 is due Sunday on MP • Coming week recitation quiz will be on Chapter 3 Speeder A speeder passes you (a police officer) sitting by the side of the road and maintains their constant velocity V. You immediately start to move after the speeder from rest with constant acceleration a. • How much time does it take to ram the speeder? • How far do you have to travel to catch the speeder? • What is your final speed? Police Officer Speeder X Throw a Ball up You throw a ball upward into the air with initial velocity V0. Calculate: a) The time it takes to reach its highest point (the top). b) Distance from your hand to the top c) Time to go from your hand and come back to your hand d) Velocity when it reaches your hand e) Time from leaving your hand to reach some random height h. Chapter 3 • Kinematics in Two or Three Dimensions • Projectile Motion • Uniform Circular Motion Important Equations of Motion If the acceleration is constant v = v 0 + at 2 1 x = x 0 + v 0 t + 2 at Position, velocity and Acceleration are vectors. Projectile Motion The horizontal and vertical equations of the motion behave independently Problem solving: The trick for all these problems is to break them up into the X and Y directions. Constant Acceleration x = x 0 +v 0x t + a x t 1 2 2 2 2 1 1 R = r0 +v 0 t + 2 at y = y0 +v 0y t + 2 a y t v = v 0 + at v x = v 0x +a x t v y = v 0y +a y t Kinematics in 3D Projectile Motion & Frames of Reference Checkpoint 1 A physics demo launches one marble horizontally while at the same instant dropping a second marble straight down. Which one hits the ground first? A) The launched marble hits first. B) The dropped marble hits first. C) They both hit at the same :me. Lets check again Ball Dropping • Analyze Vertical and Horizontal separately!!! • Ay = g (downwards) • Ax = 0 – Constant for Both cases!!! Vx = 0 Vx>0 Projectile Motion The horizontal and vertical equations of the motion behave independently Problem solving: The trick for all these problems is to break them up into the X and Y directions. Projectile Motion Horizontal Vertical Boring Monkey Troubles • You are a vet trying to shoot a tranquilizer dart into a monkey hanging from a branch in a distant tree. You know that the monkey is very nervous, and will let go of the branch and start to fall as soon as your gun goes off. In order to hit the monkey with the dart, where should you point the gun before shooting? • A) Right at the monkey • B) Below the monkey • C) Above the monkey Shooting the Monkey… Dart x = vo t 1 y = − gt 2 2 Monkey x = xo 1 y = − gt 2 2 Shooting the Monkey… S:ll works even if you shoot upwards! y = voy t - 1/2 g t 2 y = yo - 1/2 g t 2 Dart hits the monkey • Checkpoint 2 A destroyer simultaneously fires two shells with the same initial speed at two different enemy ships. The shells follow the trajectories shown. Which ship gets hit first. Destroyer Enemy 1 A) Enemy 1 B) Enemy 2 C) They are both hit at the same :me Enemy 2 Checkpoint 2 • …Which enemy ship gets hit first? • A) Enemy 1 B) Enemy 2 C) Same Destroyer Enemy 1 Enemy 2 A) they are traveling at the same speed, but the enemy one trajectory is shorter B) Both shots were accelera:ng towards the ground at the same rate, but the shot fired at Enemy 2 did not go as high and therefore took less :me to fall back to the ground. C) we are given that two shells are fired at same speed. therefore, both ships should get hit at the same :me. Checkpoint 3 • A destroyer fires two shells with different initial speeds at two different enemy ships. The shells follow the trajectories shown. Which enemy ship gets hit first? Destroyer Enemy 1 A) Enemy 1 B) Enemy 2 C) They are both hit at the same time Enemy 2 Checkpoint 3 • …Which enemy ship gets hit first? • A) Enemy 1 B) Enemy 2 C) Same Destroyer Enemy 1 Enemy 2 A) Since the ini:al speed for the first shell is lower, Enemy Ship 1 will be hit first. B) The ini:al speed of the shell fired at ship 2 is greater, so ship 2 gets hit first. C) they both achieve the same height so they remain in the air the same amount of :me Marbles & Math • Prove mathematically that an object projected horizontally will reach the ground at the same time as an object dropped vertically FINISHED HERE Firing up in the air at an angle A ball is fired up in the air with velocity Vo and angle Θo. Ignore air friction. The acceleration due to gravity is g pointing down. What is the final velocity here? Football Punt • A football is kicked at angle Θ0 with a velocity V0. The ball leaves the punters foot h meters above the ground. – The velocity at the maximum height – How far does it travel, in the X direction, before it hits the ground? – What angle maximizes the distance traveled h In the previous problem, which of the given angles minimizes the horizontal distance traveled? A. B. C. D. θ=10 degrees θ=30 degrees θ=60 degrees θ=90 degrees Checklist for Today • For the rest of this week: – Be ready for the lab (WebAssign) including pre-labs – Quiz at the recitation on Chapter 3 – There was a pre-lecture for today • Many people completed, but not all – A pre-lecture due Wednesday morning • Don’t forget the checkpoints – Homework for Chapter 3 is due Sunday on MP • Coming week recitation quiz will be on Chapter 3 Uniform Circular Motion • Fancy words for moving in a circle with constant speed • We see this around us all the time – Moon around the earth – Earth around the sun – Merry-go-rounds Uniform Circular Motion Velocity • Velocity vector = | V| tangent to the circle • Is this ball accelerating? – Why? Centripetal Acceleration a = dv / dt ≈ (v2 − v1 ) / dt R a • Vector difference V2 - V1 gives the direction of acceleration a Centripetal Acceleration • “Center Seeking” • Accel vector= V2/R a = towards the center • Acceleration is perpendicular to rˆ direction velocity 2 v (−rˆ) R R Circular Motion: Get the speed! Speed = distance/time ! Distance in 1 revolution divided by the time it takes to go around once !Speed = 2πr/T Note: The time to go around once is known as the Period, or T Ball on a String • A ball at the end of a string is revolving uniformly in a horizontal circle (ignore gravity) of radius R. The ball makes N revolutions in a time t. • What is the centripetal acceleration? In previous problem, how would acceleration change if the number of revolutions N were to double? A. Acceleration will be ½ of the original value B. Acceleration with be double original value C. Acceleration will be quadruple original value D. Acceleration will be ¼ of the original value Firing up in the air at an angle A ball is fired up in the air with velocity Vo and angle Θo. Ignore air friction. The acceleration due to gravity is g pointing down. What is the final velocity here? Boat on the River • You want to cross the river so that the boat gets exactly from A to B. The river has a current vC=4 km/h. Your boat’s speed in still water is vB=20km/h? • What is the angle θ you should aim at to do that? θ vB In previous problem, is it possible to get from A to B for any values for vB and vC? A. B. C. D. Yes, always possible Only possible if vB>vC Only possible if vB>2vC Only possible if vB>>vC (much larger) vC θ vB Next time… • Reading: Finish Chapter 3 if you haven’t already • Homework: – HW1 was due yesterday – HW2 covered in recitation this week; due Monday (6 days from now) – Start working on HW3 • Next time: More on kinematics in two dimensions – Reading Quiz hints: Q3.13-Q3.16 A pendulum swings in an arc, at what point (of the three points A, B, C) is the magnitude of the acceleration in the x direction greatest? A. B. C. D. A B C Same at all points After leaving the gun a projectile moves in a parabolic path without air resistance. Which statement is TRUE? A. a is parallel to v along its path. B. a is perpendicular to v at top of the parabola. C. a is perpendicular to v along its path. D. a is parallel to v at the top of the parabola.