ACTS 4302 Instructor: Natalia A. Humphreys SOLUTION TO HOMEWORK 7
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ACTS 4302 Instructor: Natalia A. Humphreys SOLUTION TO HOMEWORK 7
ACTS 4302 Instructor: Natalia A. Humphreys SOLUTION TO HOMEWORK 7 Lesson 13: Asian, Barrier, and Compound options. Sufficient work must be shown to get credit for a correct answer. Partial credit may be given for incorrect answers which have some positive work. Problem 1 You are given the following binomial tree for stock prices. Each period is one year. 43.2 36 30 28.8 24 19.2 A 2-year arithmetic annual average strike Asian call option on this stock is priced using this binomial tree. You are given: (i) r = 0.05 (ii) δ = 0.03 Determine the price of the option. (A) 1.24 (B) 1.60 (C) 1.52 (D) 1.79 (E) 2.13 Solution. In the tree u = 1.2 and d = 0.8 at all nodes. The risk-neutral probability of an up is e0.02 − 0.8 e(r−δ)h − d = = 0.5505; 1 − p∗ = 0.4495 u−d 0.4 The stock prices and their averages are: p∗ = Scenario Yr 1 Yr 2 Arith Average Payoff Probability uu 36 43.2 39.6 3.6 0.55052 = 0.3031 ud 36 28.8 32.4 0 0.5505 · 0.4495 = 0.2474 du 24 28.8 26.4 2.4 0.4495 · 0.5505 = 0.2474 dd 24 19.2 21.6 0 0.44952 = 0.2020 Therefore, the average payoff is 0.3031 · 3.6 + 0.2474 · 2.4 = 1.6849 Discounting for two years, the value of the option is 1.6849 · e−2·0.05 = 1.5245 Problem 2 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS You are given the following binomial tree of stock prices. Each period of the tree is one month. 69.12 57.6 48 48 48 40 33.33 40 48 40 33.33 33.33 33.33 27.78 23.15 A 3-month geometric monthly average strike Asian put option is priced using this tree. You are given: (i) r = 0.03 (ii) δ = 0.01 Calculate the value of the price of the option. (A) 2.23 (B) 2.25 (C) 2.27 (D) 2.46 (E) 2.59 Key: A Solution. In the tree u = 1.2 and d = 1.2−1 = 0.8333 at all nodes. The risk-neutral probability of an up is 1 e0.02· 12 − 0.8333 0.1683 e(r−δ)h − d = = = 0.4591 p = u−d 1.2 − 0.8333 0.3667 1 − p∗ = 0.5409 ∗ The stock prices and their averages are: Scenario Per 1 Per 2 Per 3 Geom Average Payoff Probability uuu 48 57.60 69.12 57.60 0 0.0968 uud 48 57.60 48 51.01 3.0076 0.1140 udu 48 40 48 45.17 0 0.1140 udd 48 40 33.33 40 6.6667 0.1343 duu 33.33 40 48 40 0 0.1140 dud 33.33 40 33.33 35.42 2.0886 0.1343 ddu 33.33 27.78 33.33 31.37 0 0.1343 ddd 33.33 27.78 23.15 27.78 4.6293 0.1583 Therefore, the average payoff is 3.0076 · 0.1140 + 6.6667 · 0.1343 + 2.0886 · 0.1343 + 4.6296 · 0.1583 = 2.2516 Discounting for three months, the value of the option is 2.2516 · e−0.25·0.03 = 2.2348 ≈ 2.23 Page 2 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS Problem 3 St is the price of a nondividend paying stock at time t. You are given: (i) The stock follows the Black-Scholes framework. (ii) S0 = 55 (iii) α = 0.10 (iv) σ = 0.25 √ (v) U = S1 S2 Calculate the standard deviation of ln U . Solution. Let Q1 = S(1) S(2) and Q2 = S(0) S(1) Then S1 S2 S1 · S0 · · = S02 · Q21 · Q0 S1 S2 = S0 · S0 S0 S1 Qi are independent and are each lognormal with parameters m and v. 1 1 U = (S1 S2 ) 2 = S0 · Q1 · Q02 ln U = ln S0 + R, where R = ln Q1 + 1 ln Q2 2 1 3 E[R] = m + m = m 2 2 1 5 V ar[R] = V ar[U ] = v 2 + v 2 = v 2 = 0.078125 4√ 4 √ p p √ 5 5 V ar[ln U ] = V ar[R] = v= · 0.25 = 0.2795 (v = σ t) 2 2 Note that 3 E[ln U ] = ln 55 + (0.1 − 0.5 · 0.252 ) = 4.1105 2 Problem 4 For 3-month options on a stock with strike price 40, you are given: (i) The stock’s price is 40. (ii) δ = 0.03. (iii) A European put option has premium 1.70. (iv) A down-and-in call option with barrier 35 and strike price 40 has premium 0.95. (v) The continuously compounded risk-free interest rate is 6%. Determine the premium for a 3-month down-and-out call option with barrier 35 and strike price 40. (A) 0.45 (B) 0.75 (C) 1.05 (D) 1.35 (E) 2.95 Key: C Solution. By the parity relationship for barrier options having the same barrier: Knock-in option + Knock-out option = Ordinary option Therefore, Cdown-and-out = C − Cdown-and-in By PCP for a dividend paying stock with continuous dividends: C(S, K, T ) − P (S, K, T ) = S0 e−δT − Ke−rT ⇒ C = 1.7 + 40 · e−0.03·0.25 − 40 · e−0.06·0.25 = 1.9966 Hence, Cdown-and-out = 1.9966 − 0.95 = 1.0466 ≈ 1.05 Page 3 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS Problem 5 For a stock with price 40, you have the following portfolio of barrier options, all expiring in 3 months: (i) An up-and-in call, barrier 45, exercise price 40. (ii) An up-and-in call, barrier 50, exercise price 40. (iii) An up-and-out call, barrier 45, exercise price 40. (iv) An down-and-in call, barrier 35, exercise price 45. (v) An down-and-in put, barrier 35, exercise price 40. (vi) A down deferred rebate, barrier 32, payoff 5. During the 3 month period, the minimum stock price is 31 and the maximum stock price is 47. The final price is 44. Determine the total payoff at the end of 3 months. Solution. The following table shows payoff for each option: Option Payoff (i) 4 (ii) 0 (iii) 0 (iv) 0 (v) 0 (vi) 5 Thus, the total payoff is 9. Brief explanations: (i) max(S) = 47 > barrier of 45 ⇒ barrier is met ⇒ C = max(0, 44 − 40) = 4. (ii) barrier is not met ⇒ C = 0. (iii) barrier is met, out option ⇒ C = 0. (iv) min(S) = 31 > barrier of 35 ⇒ barrier is met ⇒ C = max(0, 44 − 45) = 0. (v) max(0, 40 − 44) = 0. Problem 6 For a stock following the Black-Scholes framework: (i) The current price is 90. (ii) The stock pays a dividend of 2 at the end of 3 months. (iii) The continuously compounded risk-free interest rate is 4%. (iv) σ = 0.3. Let S(t) be the price of the stock at time t. Calculate the current value to the buyer of an agreement to pay the buyer the maximum of 100 and the stock price at the end of 4 months. Solution. In general, max(S, K) = K + max(S − K, 0) The agreement pays max(S(t), 100) = 100 + max(S(t) − 100, 0) The present value of the above maximum is 1 100e−0.04· 3 + C Page 4 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS The pre-paid forward on the stock is F P (S) = S0 − P V (Div) = 90 − 2e−0.04·0.25 = 90 − 1.9801 = 88.02 Using F P (S) for S and δ = 0 in the Black-Scholes Formula for a stock, we get: C = SN (d1 ) − Ke−rt N (d2 ), where ln 88.02 + 0.5 · 0.32 ln (S/K) + (r − δ + 0.5σ 2 )t 100 + 0.04q √ d1 = = σ t 0.3 13 1 3 =− 0.0993 = −0.5732 0.1732 N (d1 ) = N (−0.57) = 1 − N (0.57) = 1 − 0.7157 = 0.2843 √ d2 = d1 − σ t = −0.5732 − 0.1732 = −0.7464 N (d2 ) = N (−0.75) = 1 − N (0.75) = 1 − 0.7734 = 0.2266 1 Ke−rt = 100e−0.04· 3 = 98.6755 C = 88.02 · 0.2843 − 98.6755 · 0.2266 = 25.0241 − 22.3599 = 2.6642 Therefore, the current value to the buyer of an agreement to pay the buyer the maximum of 100 and the stock price at the end of 4 months is: 1 100e−0.04· 3 + 2.6642 = 98.6755 + 2.6642 = 101.3397 Problem 7 For a stock you are given: (i) The current price is 50. (ii) The continuous dividend rate is 0.02 (iii) The continuously compounded risk-free interest rate is 6%. Compound options with strike price 5.00 and 3-month expiry allow buying an option on the stock expiring 1 year from now with a strike price of 55. The following table has prices for 3 of the 4 compound options. Premium for . . . Call Put Call on . . . 1.8 Put on . . . 1.25 3.6 Determine the price of the Put on Put option. (A) −1.54 (B) −0.27 (C) 0.26 (D) 1.25 (E) 3.05 Key: C Solution. Parity relationships for compound options: P utOnP ut = CallOnP ut − P + xe−rt1 C = CallOnCall − P utOnCall + xe−rt1 P = C − Se−δt + Ke−rt Using the values given: C = 1.8 − 1.25 + 5e−0.06·0.25 = 5.4756 P = 5.4756 − 50e−0.02·1 + 55e−0.06·1 = 5.4756 − 49.0099 + 51.7971 = 8.2627 P utOnP ut = 3.6 − 8.2627 + 5e−0.06·0.25 = 3.6 − 8.2627 + 4.9256 = 0.2629 ≈ 0.26 Page 5 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS Problem 8 For a European call-on-call option: (i) The price of the underlying stock is 45. (ii) The stock’s annual volatility is 0.3. (iii) The continuous annual dividend rate is 2% (iv) The continuously compounded risk-free rate is 5%. (v) For the call-on-call option, the premium is 0.75, time to expiry is 3 months, and the strike price is 5. (vi) For the underlying call option, time to expiry is 6 months and the strike price is 45. (vii) Options are priced using the Black-Scholes formula. Determine the premium for a European put-on-call option with the same underlying asset and strike price. (A) 1.35 (B) 1.61 (C) 2.27 (D) 2.31 (E) 2.85 Key: B Solution. We are given: S0 = 45, σ = 0.3, δ = 2%, r = 5%, CC = 0.75, t1 = 0.25, x = 5, K = 45, t = 0.5. We need to find P C. By definition of a compound option, for t0 < t1 < T , CC allows buying a call option at time t1 and P C allows selling a call option at time t1 . By the parity relationships for compound options: CallOnCall(S, K, x, σ, r, t1 , t, δ) − P utOnCall(S, K, x, σ, r, t1 , t, δ) = C(S, K, σ, r, t, δ) − xe−rt1 and C = Se−δt N (d1 ) − Ke−rt N (d2 ) The underlying call value is ln 45 + 0.05 − 0.02 + 0.5 · 0.32 ln (S/K) + (r − δ + 12 σ 2 )t q √ = 45 d1 = σ t 0.3 12 1 2 =− 0.0375 = 0.1768 0.2121 N (d1 ) = N (0.1768) = 0.5702 √ d2 = d1 − σ t = 0.1768 − 0.2121 = −0.0354, N (d2 ) = N (−0.0354) = 0.4859 Se−δt = 45e−0.02·0.5 = 44.5522, Ke−rt = 45e−0.05·0.5 = 43.8889 C = 44.5522 · 0.5702 − 43.8889 · 0.4859 = 4.0763 By the parity relationships for compound options: P utOnCall(S, K, x, σ, r, t1 , t, δ) = CallOnCall(S, K, x, σ, r, t1 , t, δ) − C(S, K, σ, r, t, δ) + xe−rt1 = = 0.75 − 4.0763 + 5 · e−0.05·0.25 = 0.75 − 4.0763 + 4.9379 = 1.6116 ≈ 1.61 Problem 9 A 6-month European put-on-call option is modeled with a 1-year 2-period binomial tree with u = 1.2, d = 0.8. You are given: (i) The price of the underlying stock is 50. (ii) The continuous annual dividend rate is 0.03. (iii) The strike price of the underlying call is 55. (iv) The underlying call expires in 1 year. (v) The strike price of the put-on-call is 0.6. (vi) The continuously compounded risk-free rate is 0.05. Determine the premium of the put-on-call option. (A) 0 (B) 0.26 (C) 0.28 (D) 4.15 (E) 7.67 Key: C Page 6 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS Solution. The stock and the call trees are 72 60 50 48 40 32 17 Cu 0 C Cd 0 The risk-neutral probability is: e(r−δ)h − d e0.02·0.5 − 0.8 = = 0.5251; 1 − p∗ = 0.4749 u−d 0.4 Calculate the value of the underlying call: p∗ = Cu = e−0.05·0.5 · 0.5251 · 17 = 8.7067, Cd = 0 C = e−0.05·0.5 · 0.5251 · 8.7067 = 4.4592 Thus, the call tree is: 17 8.7067 4.4592 0 0 0 And the corresponding 6-month put is: 0 PC 0.6 Page 7 of 8 Copyright ©Natalia A. Humphreys, 2014 ACTS 4302. AU 2014. HW7 SOLUTIONS Therefore, P C = e−0.05·0.5 · 0.4749 · 0.6 = 0.2779 ≈ 0.28 Problem 10 You are given the following binomial tree for stock prices. Each period is one year. 101.4 78 60 54.6 42 29.4 You are given that r = 0.05 and δ = 0.02. A two-year up-and-in barrier call option with barrier 70 and strike price 65 is priced using this tree. It is assumed that the price movements within each period are monotonic. Determine the price of this call option. (A) 0 (B) 2.33 (C) 8.83 (D) 9.99 (E) 11.29 Key: D Solution. u = 1.3 and d = 0.7 at all nodes. Then 0.3305 e0.05−0.02 − 0.7 = = 0.5508, 1 − p∗ = 0.4492 p∗ = 1.3 − 0.7 0.6 The option only pays if the stock price first goes up to 78, but then it pays only at 101.4 node. The payoff is 36.4 at this node. It is zero at all other nodes. Calculating the expected value of 1 path and discounting: Cui = e−2·0.05 · 36.4 · 0.55082 = 9.9922 ≈ 9.99 Page 8 of 8