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MATHEMATICS Decimal Placement in a Product or Quotient Multiplying and dividing decimal numbers is similar to multiplying and dividing nondecimal numbers. The main difference is that after the multiplication or division occurs in computations involving decimals, the correct placement of the decimal needs to be determined. The process for multiplying decimals is as follows: Step 1. Set up the problem as if the numbers are whole numbers, without paying specific attention to the decimal points. Step 2. Multiply the numbers without paying specific attention to the decimal points. Step 3. Once the multiplication is complete, count the total number of decimal places in the factors. Step 4. Starting from the far right end of the product, count back (to the left) the number of decimal places you counted in step 3. Step 5. Put the decimal point in this spot. Finished! Examples 2.10 and 2.11 apply these steps. Example 2.10: Multiply 5.62 and 0.3. __________________________________________________________________________________________ Step 1. 562 ×3 Step 2. 562 ×3 1686 Step 3. In this problem, we had 5.62 with 2 decimal places and 0.3 with just one decimal place. This is a total of 3 decimal places. Step 4. Count back 3 decimal places from the end of 1686. Step 5. The decimal belongs between the 1 and the 6. The final answer is 1.686. TEAS® STUDY MANUAL 59 MATHEMATICS Example: Simplify the expression: 11.4 cm 7 cm 3.06 cm Example: Simplify the expression: 11.4 cm 7 cm 3.06 cm Example 2.11: ____________________________________________________________ Simplify the expression: 11.4 cm × 7 cm × 3.06 cm. ____________________________________________________________ __________________________________________________________________________________________ Step 1.1. Step Step1. 114 114 306 Simplify the expression: 11.4 cm 7 cm 3.06 cm 306 ____________________________________________________________ Step 2. Step 2. Step 2. 114 114 7 Step 1. 114 798 7987 798 798 798 × 306 306 ______ 306 4788 4788 306 4788 00000 00000 00000 239400 Step 2. +________ 239400 239400 244188 114 244188 244188 7 Step 3. In this problem, we had 11.4 with 1 decimal place and 3.06 with 2 798 3. 798 In this problem, we had with 1decimal decimal place and 3.06 2 with 2 decimal places. This is a Step Step 3.decimal In this problem, wea 11.4 had 1 decimal place andwith 3.06 places. This is total11.4 of 3 with places. 306 This is aplaces. total of 3 decimal places. decimal totalplaces. of 3 decimal 4788 Step 4. Starting from the far right end of the product, count back (to the 00000 Step 4. Starting from the3offar right end of the count back Step 4.left) Count back decimal places from the end 244188. the number decimal places youproduct, counted inofstep 3. (to the 239400 left) the number of decimal places you counted in step 3. 244188 Step 5.Count The decimal belongs between theend 4 and the 1. The final answer is 244.188 cm. back 3 decimal places from the of 244188. Count back 3 decimal places from the end of 244188. Step 3. dividing In this problem, we had is 11.4 1 decimal place and 3.06 with 2 The process for aswith follows: Step 5. decimals The decimal belongs between the 4 and the 1. The final answer is decimal is a belongs total of 3between decimalthe places. Step places. 5. 244.188 TheThis decimal 4 and the 1. The final answer is cm. a __ cm. 244.188 Step 1. Set up the problem to be an equivalent problem in which the divisor (b in b ) is a whole number by Step 4. Starting from the far right end of the product, count a back (to the __ ) the decimal point in the dividend (a ininbstep The processmoving for dividing decimals is as follows: left)the thedecimals numberis of places you counted 3. same number of places that the decimal point The process for dividing asdecimal follows: Example: is moved in the divisor. Step 1. Set up the problem todecimal be an equivalent problem inofwhich the divisor is a whole Count back 3to places from the end 244188. Step2. 1. Set up the problem be an equivalent problem which thepoint divisor a whole Step When performing division, theindecimal inisthe number by moving thelong decimal point inplace the dividend the same number of quotient places thatdirectly above the decimal point number moving the decimal point in the dividend the same number of places that in decimal the by dividend. the point is moved in the divisor. Step 5. The decimal belongs between the 4 and the 1. The final answer is the decimal point is moved in the divisor. 244.188 cm. Step 3. For Divide the equation as ifwere it were number. example, if the problem 0.48a ÷whole 1.2, then rewrite the problem as 4.8 ÷ 12 by For example, if the problem were 0.48 ÷ 1.2, then rewrite the problem as 4.8 ÷ 12 by moving the is decimal point to the right in both the dividend and divisor. Alternatively, The process for dividing decimals as follows: moving the decimal point to the right in both the dividend and divisor. Alternatively, Example 2.12 applies steps. rewrite thethese problems as: rewrite the problems as: Step 1. Set up the problem to be an equivalent problem in which the divisor is a whole 12 4.8 1.2 0.48 number by moving the decimal point in the dividend the same of places that 1.2 00.48 .48 12 number 4.8 Example 2.12: Simplify the expression: ÷ 1.2. the decimal point is moved in the divisor. __________________________________________________________________________________________ For example, if the problem were 0.48 ÷ 1.2, then rewrite the problem as 4.8 ÷ 12 by 1. right Rewrite thethe problem as and 4.8 divisor. ÷ 12 by Alternatively, moving the decimal point to the right in both the moving the decimal pointStep to the in both dividend dividend and85 divisor. Alternatively, rewrite the problems as: rewrite the problems as: 85 Step 2. When performing long division, the decimal the directly above place 0.48 point 12in .8 quotient Step 2. When performing long division, place the1.2 decimal point in4the quotient directly above the decimal point in the dividend. Continuing the example: the decimal point in the dividend. Continuing the example: . . 12 4.8 12 4.8 85 Step 3. Divide the equation as if it were a whole number. Continuing the example: Step 3. Divide the equation as if it were a whole number. Continuing the example: Step 3. .4 .4 12 4.8 12 4.8 – 4.8 4.8 0 0 Step 2. ractice ractice problems problems olutions problems olutions to to the the practice practice problems are are located located in in the the back back of of this this book. book. 60 Compute the product of 6.3 and 7.6. Compute the product of 6.3 and 7.6. TEAS® STUDY MANUAL MATHEMATICS Practice problems Solutions to the practice problems are located in the back of this book. 1. Compute the product of 6.3 and 7.6. 2. Divide 0.05 into 0.710. 3. Simplify the expression: 0.3 × 0.12. 4. Simplify the expression: 0.4 ÷ 0.02. TEAS® STUDY MANUAL 61