# Mathematics - Paper - II (Set

## Transcription

Mathematics - Paper - II (Set
```MODEL PAPER - 5
1
CONTINUOUS & COMPREHENSIVE EVALUATION
SUMMATIVE ASSESSMENT - III
MODEL PAPER - 5
MATHEMATICS - PAPER - II
X CLASS
Max Marks : 40]
[Time : 2 : 45 hrs
SECTION - I
Note : 1.
2.
7×1=7M
Each question carries one mark
.
d
a
1.
Find the area of Rhombus when one side is 20 cm and one diagonal is 24 cm.
2.
A group of 10 items has mean equal to 6. If the mean of 4 of these items is 7.5. What is the mean
of remaining items.
3.
Value of Cos 1o . Cos 2o ..... Cos 179o.
4.
A die is thrown once. Find the probability of getting (a) prime no. (b) No between 2 and 6 (c) an
5.
Draw a circle and two lines parallel such that one is a tangent and the other secant to the circuit.
6.
Let  ABC ~  DEF and their areas be respectively 64 cm2, 121 cm2. If EF = 15.4 Find BC
7.
Write the formula for mode and explain the terms in it.
Note : 1.
2.
8.
,
B
E
C
D
b
a
r
e
d
y
H
SECTION - II
6 × 2 = 12 M
Each question carries two mark
If the class intervals of a frequency distribution are 16 - 25, 26 - 35, 36 - 45 then find
(a) class intervals and class boundaries of 36 - 45
(b) class mark and class size of 26 - 35
(c) the class intervals when changed to continuous classes.
9.
A rectangular strip 16 cm × 3.5 cm is rotated along the longer side. Find volume and total surface
area of solid generated.
10.
If Tan  + Cot  = 2 what are values of sec .
11.
ST if the hypotenuse of 90o, 60o, 30o triangle is hem, the other two sides are h/2 cm and
h
2 3 cm.
12.
The cost of fencing a circular field at the rate of Rs. 24 per meter is Rs. 5280. The field is to be
ploughed at the rate of 0.50 ps per m2. Find the cost of ploughering the field.
13.
Give two examples for similar and congruent shapes.
MATHEMATICS - PAPER - II
2
SECTION - III
Note : 1.
2.
14.
4 × 4 = 16 M
Internal choice is given in each question.
Each question carries four mark
(a) If 8 tan A = –15 25 Sin B = –7. A and B are not in 4th Quadrant.
ST Sin A Cos B + Cos A Sin B = – 304 425
OR
(b) The mean of the following frequency table is 50. But the frequencies f1 and f2 are missing in
20 – 40 and 60 – 80 classes. Find the missing frequencies.
Class Interval 0  20 20  40 40  60 60  80 80  100 Total
Frequency
17
f1
32
f2
19
120
15.
.
d
a
(a) The diameter of a Roller 120 cm long is 84 cm. If it takes 500 complete revolutions to level
a play ground. Determine the cost of levelling it at the rate of Rs. 0.50 per sq. m.
b
a
r
e
d
y
H
OR
(b) A bag consists of 144 pencils of which 20 were broken. The shop keeper draws one pencil
at random and gives it to the customer. What is the probability (a) he will buy it. (b) He will
not by it.
16.
(a) The following distribution gives the daily income of 50 workers. Working in a factory.
Draw the give curves.
,
B
E
C
D
Daily Wage 100  120 120  140 140  160 160  180 180  200
Wor ker s
12
14
8
6
10
OR
(b) Solve 2x + 3y = 8, 4x + 6y = 7 graphically.
17.
(a) Write answer for questions pertaining to figure give below :
A
B
(i)
D
C
If AC = AB which angles are equal
(ii) If  ABC =  ACB which too sides are equal
(iii) If AC = BC = AB which angles are equal and what is measure of each angle
(iv) In  ABC AC > AB compare angles  ABC and  ACB.
OR
MODEL PAPER - 5
3
(b) Find the value of
Sin 2
Cos2
–
– Cos  + Sin 
1  Cos 1  Sin
SECTION - IV
Note : 1.
Each question carries
XY
YP
=
XZ
PZ
XY
PZ
=
XZ
XP
(b) –Tan 
,
B
E
C
D
(b) 45o
(
b
a
r
e
d
y
H
(c) 1.25
(
)
(
)
(
)
(
)
)
(d) 1.6
)
(c) Cot 
(c) 3
(d) –Cot 
(d) 4
(c) 60o
(c) 10
)
XZ
YP
=
XY
YZ
(d) 90o
The diagonal of a square is 5 2 cm then area in
(b) 5 cm2
(
.
d
a
(d)
The length of shadow of tower is equal to its height then angle of elevation is
2 cm2
(d) 25
2 cm2
The number of circles that can be drawn passing through three points which are not collinear.
(
)
(b) 2
(c) 3
(d) 4
The arithmetic mean of n even natural numbers is
(a) n(n + 1)
27.
(c)
(
(b) 2
(a) 1
26.
=5M
(d) 7.8
Two coins are simultaneously tossed then no. of all possible outcomes is
(a) 25 cm2
25.
XY
XZ
=
PZ
YP
Tan (90 + ) =
(a) 30o
24.
(b)
(b) 1.5
(a) 1
23.
(c) 5.4
Median of 1.3, 1.5, 1.25 is
(a) Tan 
22.
2
mark.
(b) 8.1
(a) 1.3
21.
2
In a le XYZ if interval bisector of X meets YZ in P then
(a)
20.
1
 ABC ~  PQR AB = 3.6 PQ = 2.4 PR = 5.4 then AC =
(a) 3.6
19.
1
2.
18.
10 ×
(b)
n 1
2
(c) n
(b) zero
(c) maximum
)
(
)
(d) n + 1
Sum of deviations from the mean is
(a) least
(
(d) none
```