Compilerbau - DHBW Stuttgart
Transcription
Compilerbau - DHBW Stuttgart
Compilerbau Stephan Schulz [email protected] Code-Generierung Semantik Optimierung Scanner Parser AST Table of Contents Preliminaries Introduction Refresher: Flex and Bison Exercise 1: Scientific Calculator Syntax Analysis Example Language: nanoLang Grammars and Derivations Semantic Analysis Runtime Environment and Code Generation 2 , Introduction I Stephan Schulz I I I I I I Dipl.-Inform., U. Kaiserslautern, 1995 Dr. rer. nat., TU München, 2000 Visiting professor, U. Miami, 2002 Visiting professor, U. West Indies, 2005 Visiting lecturer (Hildesheim, Offenburg, . . . ) seit 2009 Industry experience: Building Air Traffic Control systems I I I System engineer, 2005 Project manager, 2007 Product Manager, 2013 I Professor, DHBW Stuttgart, 2014 3 , Introduction I Stephan Schulz I I I I I I Dipl.-Inform., U. Kaiserslautern, 1995 Dr. rer. nat., TU München, 2000 Visiting professor, U. Miami, 2002 Visiting professor, U. West Indies, 2005 Visiting lecturer (Hildesheim, Offenburg, . . . ) seit 2009 Industry experience: Building Air Traffic Control systems I I I System engineer, 2005 Project manager, 2007 Product Manager, 2013 I Professor, DHBW Stuttgart, 2014 Research: Logic & Deduction 3 , Goals for Today I Practical issues I Programming language survey I Execution of languages I Low-level code vs. high-level code I Structure of a Compiler Refresher I I Grammars I Flex/Bison I Programming exercises I Scientific calculator revisited 4 , This Course in Context I Formal languages and automata I I I I Basic theory - languages and automata General grammars Abstract parsing Computability Focus on foundations I Compiler construction I I I I Advanced theory - parsers and languages Tools and their use Writing parsers and scanners Code generation and run times Focus on practical applications 5 , Practical issues I Lecture time: Wednesdays, 12:30-16:45 I I I I I Lecture (with exercises): 12:30-14:45 Lab: 15:00-16:45 Breaks will be somewhat flexible No lecture on March 25th (I’m snowboarding) Grading: I Lecture Compilerbau: Written Exam, grade averaged with Formal Languages&Automata for module grade I Lab: Pass/Fail based on success in exercises 6 , Computing Environment I For practical exercises, you will need a complete Linux/UNIX environment. If you do not run one natively, there are several options: I You can install VirtualBox (https://www.virtualbox.org) and then install e.g. Ubuntu (http://www.ubuntu.com/) on a virtual machine. Make sure to install the Guest Additions I For Windows, you can install the complete UNIX emulation package Cygwin from http://cygwin.com I For MacOS, you can install fink (http://fink.sourceforge.net/) or MacPorts (https://www.macports.org/) and the necessary tools I You will need at least flex, bison, gcc, grep, sed, AWK, make, and a good text editor 7 , Resources I Course web page I http://wwwlehre.dhbw-stuttgart.de/~sschulz/cb2015.html I Literature I Alfred V. Aho, Monica S. Lam, Ravi Sethi, Jeffrey D. Ullman: Compilers: Principles, Techniques, and Tools I Kenneth C. Louden: Compiler Construction - Principles and Practice I Ulrich Hedtstück: Einführung in die theoretische Informatik 8 , Exercise: Programming Languages I Name and describe several modern programming languages! 9 , Modern Programming Languages Desirable properties of high-level languages I Expressive and flexible I I I I Close to application domains Good abstractions Powerful constructs Readable I Compact I Machine independent I Programmer productivity depends on length (!) I Code should run on many platforms I Code should run on evolving platforms I Strong error-checking I Static I Dynamic I Efficiently executable 10 , Low-Level Code I Machine code I I I I I I I I Binary Machine-specific Operations (and operands) encoded in instruction words Basic operations only Manipulates finite number of registers Direct access to memory locations Flow control via conditional and unconditional jumps (think goto) Basic data types (bytes, words) 11 , Low-Level Code I Machine code I I I I I I I I Binary Machine-specific Operations (and operands) encoded in instruction words Basic operations only Manipulates finite number of registers Direct access to memory locations Flow control via conditional and unconditional jumps (think goto) Basic data types (bytes, words) Directly executable by processor 11 , Low-Level Code I Machine code I I I I I I I I Binary Machine-specific Operations (and operands) encoded in instruction words Basic operations only Manipulates finite number of registers Direct access to memory locations Flow control via conditional and unconditional jumps (think goto) Basic data types (bytes, words) Directly executable by processor I Assembly languages I Textual representation of machine code I Symbolic names for operations and operands I Labels for addresses (code and data) 11 , Low-Level Code I Machine code I I I I I I I I Binary Machine-specific Operations (and operands) encoded in instruction words Basic operations only Manipulates finite number of registers Direct access to memory locations Flow control via conditional and unconditional jumps (think goto) Basic data types (bytes, words) Directly executable by processor I Assembly languages I Textual representation of machine code I Symbolic names for operations and operands I Labels for addresses (code and data) Direct one-to-one mapping to machine code 11 , Exercise: Low-Level Code – Minimal C I Predefined global variables I Integers R0, R1, R2, R3, R4 I Integer array mem[MAXMEM] I No new variables allowed I No parameters (or return) for functions Flow control: Only if and goto (not while, for, . . . ) I Arithmetic only between R0, R1, R2, R3, R4 I I No blocks after if (only one command allowed) I Result must be stored in one of R0, R1, R2, R3, R4 I Operands: Only R0, R1, R2, R3, R4 allowed (no nested sub-expressions) I Unary incement/decrement is ok (R0++) I R0, R1, R2, R3, R4 can be stored in/loaded from mem, indexed with a fixed address or one of the variables. 12 , Exercise: Minimal C Example /∗ Compute sum from 0 t o R0 , r e t u r n r e s u l t i n R1 ∗/ void user code ( void ) { /∗ R0 i s t h e i n p u t v a l u e and l i m i t ∗/ R1 = 0 ; /∗ Sum , v a l u e r e t u r n e d ∗/ R2 = 0 ; /∗ Loop c o u n t e r ∗/ R3 = 1 ; /∗ For i n c r e m e n t s ∗/ loop : i f ( R2 > R0 ) goto end ; R1 = R1+R2 ; R2 = R2+R3 ; goto l o o p ; end : return ; } 13 , Exercise: Low-Level Code I Write (in Minimal C) the following functions: I A program computing the factorial of R0 I A program computing the Fibonacci-number of R0 iteratively I A program computing the Fibonacci-number of R0 recursively I You can find a frame for your code at the course web page, http://wwwlehre.dhbw-stuttgart.de/~sschulz/cb2015.html 14 , Surprise! Computers don’t execute high-level languages (directly)! 15 , Execution of high-level programs Compiled languages Interpreted languages Development Time Run Time 16 , Execution of high-level programs Data Compiled languages Program Compiler Executable Results Interpreted languages Development Time Run Time 16 , Execution of high-level programs Data Compiled languages Program Compiler Executable Results Interpreted languages Program Data Interpreter Results Development Time Run Time 16 , Compilers Compilers translate high-level languages into low-level code! 17 , Reminder: Syntactic Structure of Computer Languages I Most computer languages are mostly context-free I Regular: vocabulary I I I Keywords, operators, identifiers Described by regular expressions or regular grammar Handled by (generated or hand-written) scanner/tokenizer/lexer I Context-free: program structure I I I Matching parenthesis, block structure, algebraic expressions, . . . Described by context-free grammar Handled by (generated or hand-written) parser I Context-sensitive: e.g. declarations I I Described by human-readable constraints Handled in an ad-hoc fashion (e.g. symbol table) 18 , High-Level Architecture of a Compiler Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 19 , Source Handler I Handles input files I Provides character-by-character access I May maintain file/line/colum (for error messages) I May provide look-ahead Result: Sequence of characters (with positions) 20 , Lexical Analysis/Scanning I I Breaks program into token Typical tokens: I Reserved word (if, while) I Identifier (i, database) I Symbols ({, }, (, ), +, -, ... Result: Sequence of tokens 21 , Exercise: Lexical Analysis i n t main ( i n t a r g c , char ∗ a r g v [ ] ) { R0 = 0 ; R1 = 0 ; R2 = 0 ; R3 = 1 ; R4 = 1 ; f o r ( i n t i = 0 ; i <MAXMEM; i ++) { mem[ i ] = 0 ; } user code (); return 0; } 22 , Automatisation with Flex Flex Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 23 , Syntactical Analysis/Parsing I I Description of the language with a context-free grammar Parsing: I Try to build a parse tree/abstract syntax tree (AST) I Parse tree unambiguously describes structure of a program I AST reflects abstract syntax (can e.g. drop parenthesis) I Methods: I Manual recursive descent parser I Automatic with a table-driven bottom-up parser Result: Abstract Syntax Tree 24 , Automatisation with Bison Flex Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Bison Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 25 , Semantic Analysis I Analyze static properties of the program I I I I I Which variable has which type? Are all expressions well-typed? Which names are defined? Which names are referenced? Core tool: Symbol table Result: Annotated AST 26 , Optimization I Transform Abstract Syntax Tree to generate better code I Smaller I Faster I Both I Mechanisms I I I I Common sub-expression elimination Loop unrolling Dead code/data elimination ... Result: Optimized AST 27 , Code Generation I I Convert optimized AST into low-level code Target languages: I I I I I Assembly code Machine code VM code (z.B. JAVA byte-code, p-Code) C (as a “portable assembler”) ... Result: Program in target language 28 , Refresher: Flex 29 , Flex Overview I I Flex is a scanner generator Input: Specification of a regular language and what to do with it I Definitions - named regular expressions I Rules - patters+actions I (miscellaneous support code) I Output: Source code of scanner I I I I Scans input for patterns Executes associated actions Default action: Copy input to output Interface for higher-level processing: yylex() function 30 , Flex Overview ! Definitions Rules Miscellanous code flex+gcc ! ! ! Input scanner ! Tokenized/ processed output 31 , Flex Overview Development time ! Definitions Rules Miscellanous code flex+gcc ! ! ! Input scanner ! Tokenized/ processed output Execution time 31 , Flex Example Task I I (Artificial) goal: Sum up all numbers in a file, separately for ints and floats Given: A file with numbers and commands I Ints: Non-empty sequences of digits I Floats: Non-empty sequences of digits, followed by decimal dot, followed by (potentially empty) sequence of digits I Command print: Print current sums I Command reset: Reset sums to 0. I At end of file, print sums 32 , Flex Example Output Input Output 12 3.1415 0.33333 print reset 2 11 1.5 2.5 print 1 print 1.0 int: 12 ("12") float: 3.141500 ("3.1415") float: 0.333330 ("0.33333") Current: 12 : 3.474830 Reset int: 2 ("2") int: 11 ("11") float: 1.500000 ("1.5") float: 2.500000 ("2.5") Current: 13 : 4.000000 int: 1 ("1") Current: 14 : 4.000000 float: 1.000000 ("1.0") Final 14 : 5.000000 33 , Basic Structure of Flex Files I Flex files have 3 sections I Definitions I Rules I User Code I Sections are separated by %% I Flex files traditionally use the suffix .l 34 , Example Code (definition section) %%option noyywrap DIGIT [0-9] %{ int intval = 0; double floatval = 0.0; %} %% 35 , Example Code (rule section) {DIGIT}+ { printf( "int: %d (\"%s\")\n", atoi(yytext), yytext ); intval += atoi(yytext); } {DIGIT}+"."{DIGIT}* { printf( "float: %f (\"%s\")\n", atof(yytext),yytext ); floatval += atof(yytext); } reset { intval = 0; floatval = 0; printf("Reset\n"); } print { printf("Current: %d : %f\n", intval, floatval); } \n|. { /* Skip */ } 36 , Example Code (user code section) %% int main( int argc, char **argv ) { ++argv, --argc; /* skip over program name */ if ( argc > 0 ) yyin = fopen( argv[0], "r" ); else yyin = stdin; yylex(); printf("Final %d : %f\n", intval, floatval); } 37 , Generating a scanner > flex -t numbers.l > numbers.c > gcc -c -o numbers.o numbers.c > gcc numbers.o -o scan_numbers > ./scan_numbers Numbers.txt int: 12 ("12") float: 3.141500 ("3.1415") float: 0.333330 ("0.33333") Current: 12 : 3.474830 Reset int: 2 ("2") int: 11 ("11") float: 1.500000 ("1.5") float: 2.500000 ("2.5") ... 38 , Flexing in detail > flex -tv numbers.l > numbers.c scanner options: -tvI8 -Cem 37/2000 NFA states 18/1000 DFA states (50 words) 5 rules Compressed tables always back-up 1/40 start conditions 20 epsilon states, 11 double epsilon states 6/100 character classes needed 31/500 words of storage, 0 reused 36 state/nextstate pairs created 24/12 unique/duplicate transitions ... 381 total table entries needed 39 , Definition Section I I Can contain flex options Can contain (C) initialization code I I I I I Typically #include() directives Global variable definitions Macros and type definitions Initialization code is embedded in %{ and %} Can contain definitions of regular expressions I Format: NAME RE I Defined NAMES can be referenced later 40 , Example Code (definition section) (revisited) %%option noyywrap DIGIT [0-9] %{ int intval = 0; double floatval = 0.0; %} %% 41 , Rule Section I This is the core of the scanner! I Rules have the form PATTERN ACTION Patterns are regular expressions I I Typically use previous definitions I I THERE IS WHITE SPACE BETWEEN PATTERN AND ACTION! Actions are C code Can be embedded in { and } Can be simple C statements For a token-by-token scanner, must include return statement Inside the action, the variable yytext contains the text matched by the pattern I Otherwise: Full input file is processed I I I I 42 , Example Code (rule section) (revisited) {DIGIT}+ { printf( "int: %d (\"%s\")\n", atoi(yytext), yytext ); intval += atoi(yytext); } {DIGIT}+"."{DIGIT}* { printf( "float: %f (\"%s\")\n", atof(yytext),yytext ); floatval += atof(yytext); } reset { intval = 0; floatval = 0; printf("Reset\n"); } print { printf("Current: %d : %f\n", intval, floatval); } \n|. { /* Skip */ } 43 , User code section I Can contain all kinds of code I For stand-alone scanner: must include main() I In main(), the function yylex() will invoke the scanner I yylex() will read data from the file pointer yyin (so main() must set it up reasonably 44 , Example Code (user code section) (revisited) %% int main( int argc, char **argv ) { ++argv, --argc; /* skip over program name */ if ( argc > 0 ) yyin = fopen( argv[0], "r" ); else yyin = stdin; yylex(); printf("Final %d : %f\n", intval, floatval); } 45 , A comment on comments I Comments in Flex are complicated I . . . because nearly everything can be a pattern I Simple rules: I I I I Use old-style C comments /* This is a comment */ Never start them in the first column Comments are copied into the generated code Read the manual if you want the dirty details 46 , Flex Miscellany I Flex online: I http://flex.sourceforge.net/ I Manual: http://flex.sourceforge.net/manual/ I REs: http://flex.sourceforge.net/manual/Patterns.html I make knows flex I Make will automatically generate file.o from file.l I Be sure to set LEX=flex to enable flex extensions I Makefile example: LEX=flex all: scan_numbers numbers.o: numbers.l scan_numbers: numbers.o gcc numbers.o -o scan_numbers 47 , Refresher: Bison 48 , YACC/Bison I Yacc - Yet Another Compiler Compiler I Originally written ≈1971 by Stephen C. Johnson at AT&T I LALR parser generator I Translates grammar into syntax analyzer I GNU Bison I Written by Robert Corbett in 1988 I Yacc-compatibility by Richard Stallman I Output languages now C, C++, Java I Yacc, Bison, BYacc, . . . mostly compatible (POSIX P1003.2) 49 , Yacc/Bison Background I By default, Bison constructs a 1 token Look-Ahead Left-to-right Rightmost-derivation or LALR(1) parser I Input tokens are processed left-to-right I Shift-reduce parser: I I I I I I I Stack holds tokens (terminals) and non-terminals Tokens are shifted from input to stack. If the top of the stack contains symbols that represent the right hand side (RHS) of a grammar rule, the content is reduced to the LHS Since input is reduced left-to-right, this corresponds to a rightmost derivation Ambiguities are solved via look-ahead and special rules If input can be reduced to start symbol, success! Error otherwise LALR(1) is efficient in time and memory I Can parse “all reasonable languages” I For unreasonable languages, Bison (but not Yacc) can also construct GLR (General LR) parsers I I Try all possibilities with back-tracking Corresponds to the non-determinism of stack machines 50 , Yacc/Bison Overview I I Bison reads a specification file and converts it into (C) code of a parser Specification file: Definitions, grammar rules with actions, support code I Definitions: Token names, associated values, includes, declarations I Grammar rules: Non-terminal with alternatives, action associated with each alternative I Support code: e.g. main() function, error handling. . . I Syntax similar to (F)lex I I I I Sections separated by %% Special commands start with % Bison generates function yyparse() Bison needs function yylex() I Usually provided via (F)lex 51 , Yacc/Bison workflow Bison Input File <file>.y Bison Flex Input file <file>.l Definitions file <file>.tab.h Flex Parser Source <file>.tab.c #include gcc Lexer Source <file>.c Parser object <file>.tab.o gcc Lexer object <file>.o linker (gcc) Some input to process Final executable parser Some output produced 52 , Yacc/Bison workflow Development time Bison Input File <file>.y Bison Flex Input file <file>.l Definitions file <file>.tab.h Flex Parser Source <file>.tab.c #include gcc Lexer Source <file>.c Parser object <file>.tab.o gcc Lexer object <file>.o linker (gcc) Some input to process Final executable parser Some output produced Execution time 52 , Example task: Desk calculator I Desk calculator I Reads algebraic expressions and assignments I Prints result of expressions I Can store values in registers R0-R99 53 , Example task: Desk calculator I Desk calculator I Reads algebraic expressions and assignments I Prints result of expressions I Can store values in registers R0-R99 I Example session: [Shell] ./scicalc R10=3*(5+4) > RegVal: 27.000000 (3.1415*R10+3) > 87.820500 R9=(3.1415*R10+3) > RegVal: 87.820500 R9+R10 > 114.820500 ... 53 , Abstract grammar for desk calculator (partial) GDC = hVN , VT , P, Si I VT = {PLUS, MULT, ASSIGN, OPENPAR, CLOSEPAR, REGISTER, FLOAT, . . . } I Some terminals are single characters (+, =, . . . ) I Others are complex: R10, 1.3e7 I Terminals (“tokens”) are generated by the lexer I VN = {stmt, assign, expr, term, factor, . . . } I P : stmt assign expr term factor I → | → → | → | → | | assign expr REGISTER ASSIGN expr expr PLUS term term term MULT factor factor REGISTER FLOAT OPENPAR expr CLOSEPAR S = *handwave* I For a single statement, S = stmt I In practice, we need to handle sequences of statements and empty input lines (not reflected in the grammar) 54 , Lexer interface I I Bison parser requires yylex() function yylex() returns token I Token text is defined by regular expression pattern I Tokens are encoded as integers I Symbolic names for tokens are defined by Bison in generated header file I I By convention: Token names are all CAPITALS yylex() provides optional semantic value of token I Stored in global variable yylval I Type of yylval defined by Bison in generated header file I I I Default is int For more complex situations often a union For our example: Union of double (for floating point values) and integer (for register numbers) 55 , Lexer for desk calculator (1) /* Lexer for a minimal "scientific" calculator. Copyright 2014 by Stephan Schulz, [email protected]. This code is released under the GNU General Public Licence Version 2. */ %option noyywrap %{ #include "scicalcparse.tab.h" %} 56 , Lexer for desk calculator (2) DIGIT INT PLAINFLOAT EXP NUMBER REG [0-9] {DIGIT}+ {INT}|{INT}[.]|{INT}[.]{INT}|[.]{INT} [eE](\+|-)?{INT} {PLAINFLOAT}{EXP}? R{DIGIT}{DIGIT}? %% "*" "+" "=" "(" ")" \n {return {return {return {return {return {return MULT;} PLUS;} ASSIGN;} OPENPAR;} CLOSEPAR;} NEWLINE;} 57 , Lexer for desk calculator (3) {REG} { yylval.regno = atoi(yytext+1); return REGISTER; } {NUMBER} { yylval.val = atof(yytext); return FLOAT; } [ ] { /* Skip . whitespace*/ } /* Everything else is an invalid character. */ { return ERROR;} %% 58 , Data model of desk calculator I Desk calculator has simple state I 100 floating point registers I R0-R99 I Represented in C as array of doubles: #define MAXREGS 100 double regfile[MAXREGS]; I Needs to be initialized in support code! 59 , Bison code for desk calculator: Header %{ #include <stdio.h> #define MAXREGS 100 double regfile[MAXREGS]; extern int yyerror(char* err); extern int yylex(void); %} %union { double val; int regno; } 60 , Bison code for desk calculator: Tokens %start stmtseq %left %left %token %token %token %token %token %token %token PLUS MULT ASSIGN OPENPAR CLOSEPAR NEWLINE REGISTER FLOAT ERROR %% 61 , Actions in Bison I Bison is based on syntax rules with associated actions I Whenever a reduce is performed, the action associated with the rule is executed I I Actions can be arbitrary C code Frequent: semantic actions I The action sets a semantic value based on the semantic value of the symbols reduced by the rule I For terminal symbols: Semantic value is yylval from Flex I Semantic actions have “historically valuable” syntax I I I I I Value of reduced symbol: $$ Value of first symbol in syntax rule body: $1 Value of second symbol in syntax rule body: $2 ... Access to named components: $<val>1 62 , Bison code for desk calculator: Grammar (1) stmtseq: /* Empty */ | NEWLINE stmtseq {} | stmt NEWLINE stmtseq {} | error NEWLINE stmtseq {}; /* After an error, start afresh */ I Head: sequence of statements I First body line: Skip empty lines I Second body line: separate current statement from rest I Third body line: After parse error, start again with new line 63 , Bison code for desk calculator: Grammar (2) stmt: assign |expr {printf("> RegVal: %f\n", $<val>1);} {printf("> %f\n", $<val>1);}; assign: REGISTER ASSIGN expr {regfile[$<regno>1] = $<val>3; $<val>$ = $<val>3;} ; expr: expr PLUS term {$<val>$ = $<val>1 + $<val>3;} | term {$<val>$ = $<val>1;}; term: term MULT factor {$<val>$ = $<val>1 * $<val>3;} | factor {$<val>$ = $<val>1;}; factor: REGISTER {$<val>$ = regfile[$<regno>1];} | FLOAT {$<val>$ = $<val>1;} | OPENPAR expr CLOSEPAR {$<val>$ = $<val>2;}; 64 , Bison code for desk calculator: Support code int yyerror(char* err) { printf("Error: %s\n", err); return 0; } int main (int argc, char* argv[]) { int i; for(i=0; i<MAXREGS; i++) { regfile[i] = 0.0; } return yyparse(); } 65 , Reminder: Workflow and dependencies Bison Input File <file>.y Bison Flex Input file <file>.l Definitions file <file>.tab.h Flex Parser Source <file>.tab.c #include gcc Lexer Source <file>.c Parser object <file>.tab.o gcc Lexer object <file>.o linker (gcc) Some input to process Final executable parser Some output produced 66 , Building the calculator 1. Generate parser C code and include file for lexer I bison -d scicalcparse.y I Generates scicalcparse.tab.c and scicalcparse.tab.h 2. Generate lexer C code I flex -t scicalclex.l > scicalclex.c 3. Compile lexer I gcc -c -o scicalclex.o scicalclex.c 4. Compile parser and support code I gcc -c -o scicalcparse.tab.o scicalcparse.tab.c 5. Link everything I gcc scicalclex.o scicalcparse.tab.o -o scicalc 6. Fun! I ./scicalc 67 , Exercise I Exercise 1 (Refresher): I Go to http://wwwlehre.dhbw-stuttgart.de/~sschulz/cb2015.html I Download scicalcparse.y and scicalclex.l I Build the calculator I Run and test the calculator I Exercise 2 (Warm-up): I Add support for division and subtraction /, I Add support for unary minus (the negation operator -) I Exercise 3 (Bonus): I Change the desk calculator so that it converts its input into a C program that will perform the same actions that the calculator performed interactively! 68 , Review: Goals for Today I Practical issues I Programming language survey I Execution of languages I Low-level code vs. high-level code I Structure of a Compiler Refresher I I Grammars I Flex/Bison I Programming exercises I Scientific calculator revisited 69 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 70 , Goals for Today I I Refresher Reminder: Grammars and Chomsky-Hierarchy I Grammars I Regular languages and expressions I Context-free grammars and languages I Syntactic structure of programming languages I nanoLang I Programming exercise: Tokenizing nanoLang 71 , Refresher I Some properties of programming languages and implementations I I I I I Object oriented vs. Procedural Imperative vs. Functional Statically typed vs. dynamically typed (vs. no types“) ” Compiled vs. interpreted High-level level languages I Expressive/Complex functionality I Features correspond to application concepts I Good abstraction I Low-level languages I I I I Simple operations Features dictated by hardware architecture (Close to) what processors can execute Limited abstraction 72 , Refresher I Structure of compiler I I I I I I I Tokenizer Parser Semantic analyis Optimizer Code generator ... Some applications of compiler technology I Implementation of programming languages I Parsing of data formats/serialization I I I I I I I E.g. Word documents - may include optimization! HTML/XML for web pages/SOA XSLT document transformers LATEX ATCCL ... Flex & Bison 73 , Refresher: Grammars 74 , Formal Grammars: Motivation Formal grammars describe formal languages! I Derviative approach I A grammar has a set of rules I Rules replace words with words I A word that can be derived from a special start symbol is in the language of the grammar 75 , Formal Grammars: Motivation Formal grammars describe formal languages! I Derviative approach I A grammar has a set of rules I Rules replace words with words I A word that can be derived from a special start symbol is in the language of the grammar In the concrete case of programming languages, “Words of the language” are syntactically correct programs! 75 , Grammars: Examples S → aA, A → bB, B→ε 76 , Grammars: Examples S → aA, A → bB, B → ε generates ab (starting from S): S → aA → abB → ab 76 , Grammars: Examples S → aA, A → bB, B → ε generates ab (starting from S): S → aA → abB → ab S → ε, S → aSb 76 , Grammars: Examples S → aA, A → bB, B → ε generates ab (starting from S): S → aA → abB → ab S → ε, S → aSb generates an b n 76 , Grammars: definition Noam Chomsky defined a grammar as a quadruple G = hVN , VT , P, Si (1) with 1. the set of non-terminal symbols VN , 2. the set of terminal symbols VT , 3. the set of production rules P of the form α→β (2) with α ∈ V ∗ VN V ∗ , β ∈ V ∗ , V = VN ∪ VT 4. the distinguished start symbol S ∈ VN . 77 , Grammars: Shorthand For the sake of simplicity, we will be using the short form α → β1 | · · · |βn replacing α → β1 .. . (3) α → βn 78 , Example: C identifiers We want to define a grammar G = hVN , VT , P, Si (4) to describe identifiers of the C programming language: I alpha-numeric words I which must not start with a digit I and may contain an underscore ( ) 79 , Example: C identifiers We want to define a grammar G = hVN , VT , P, Si (4) to describe identifiers of the C programming language: I alpha-numeric words I which must not start with a digit I and may contain an underscore ( ) VN = {I , R, L, D} (identifier, rest, letter, digit), VT = {a, · · · , z, A, · · · , Z, 0, · · · , 9, }, P={ I → LR| R|L| R → LR|DR| R|L|D| L → a| · · · |z|A| · · · |Z D → 0| · · · |9} S = I. 79 , Formal grammars: derivation Derivation: description of operation of grammars Given the grammar G = hVN , VT , P, Si, (5) we define the relation x ⇒G y iff ∃u, v , p, q ∈ V∗ : (x = upv ) ∧ (p → q ∈ P) ∧ (y = uqv ) (6) (7) pronounced as “G derives y from x in one step”. 80 , Formal grammars: derivation Derivation: description of operation of grammars Given the grammar G = hVN , VT , P, Si, (5) we define the relation x ⇒G y iff ∃u, v , p, q ∈ V∗ : (x = upv ) ∧ (p → q ∈ P) ∧ (y = uqv ) (6) (7) pronounced as “G derives y from x in one step”. We also define the relation x ⇒∗G y iff ∃w0 , . . . , wn (8) with w0 = x, wn = y , wi−1 ⇒G wi for i ∈ {1, · · · , n} pronounced as “G derives y from x (in zero or more steps)”. 80 , Formal grammars: derivation example I G = hVN , VT , P, Si with 1. VN = {S}, 2. VT = {0}, 3. P = {S → 0S, 4. S = S. (9) S → 0}, 81 , Formal grammars: derivation example I G = hVN , VT , P, Si (9) with 1. VN = {S}, 2. VT = {0}, 3. P = {S → 0S, S → 0}, 4. S = S. Derivations of G have the general form S ⇒ 0S ⇒ 00S ⇒ · · · ⇒ 0n−1 S ⇒ 0n (10) 81 , Formal grammars: derivation example I G = hVN , VT , P, Si (9) with 1. VN = {S}, 2. VT = {0}, 3. P = {S → 0S, S → 0}, 4. S = S. Derivations of G have the general form S ⇒ 0S ⇒ 00S ⇒ · · · ⇒ 0n−1 S ⇒ 0n (10) Apparently, the language produced by G (or the language of G) is L(G ) = {0n |n ∈ N; n > 0}. (11) 81 , Formal grammars: derivation example II G = hVN , VT , P, Si with 1. VN = {S}, 2. VT = {0, 1}, 3. P = {S → 0S1, 4. S = S. (12) S → 01}, 82 , Formal grammars: derivation example II G = hVN , VT , P, Si (12) with 1. VN = {S}, 2. VT = {0, 1}, 3. P = {S → 0S1, S → 01}, 4. S = S. Derivations of G have the general form S ⇒ 0S1 ⇒ 00S11 ⇒ · · · ⇒ 0n−1 S1n−1 ⇒ 0n 1n . (13) 82 , Formal grammars: derivation example II G = hVN , VT , P, Si (12) with 1. VN = {S}, 2. VT = {0, 1}, 3. P = {S → 0S1, S → 01}, 4. S = S. Derivations of G have the general form S ⇒ 0S1 ⇒ 00S11 ⇒ · · · ⇒ 0n−1 S1n−1 ⇒ 0n 1n . (13) The language of G is L(G ) = {0n 1n |n ∈ N; n > 0}. (14) 82 , Formal grammars: derivation example II G = hVN , VT , P, Si (12) with 1. VN = {S}, 2. VT = {0, 1}, 3. P = {S → 0S1, S → 01}, 4. S = S. Derivations of G have the general form S ⇒ 0S1 ⇒ 00S11 ⇒ · · · ⇒ 0n−1 S1n−1 ⇒ 0n 1n . (13) The language of G is L(G ) = {0n 1n |n ∈ N; n > 0}. (14) Reminder: L(G) is not regular! 82 , The Chomsky hierarchy (0) Given the grammar G = hVN , VT , P, Si, (15) we define the following grammar/language classes I G is of Type 0 or unrestricted 83 , The Chomsky hierarchy (0) Given the grammar G = hVN , VT , P, Si, (15) we define the following grammar/language classes I G is of Type 0 or unrestricted All grammars are Type 0! 83 , The Chomsky hierarchy (1) G = hVN , VT , P, Si, I (16) G is Type 1 or context-sensitive if all productions are of the form α1 Aα2 → α1 βα2 with A ∈ VN ; α1 , α2 ∈ V ∗ , β ∈ VV ∗ (17) Exception: S → ε ∈ P is allowed if α1 , α2 ∈ (V \{S})∗ and β ∈ (V \{S})(V \{S})∗ (18) 84 , The Chomsky hierarchy (1) G = hVN , VT , P, Si, I (16) G is Type 1 or context-sensitive if all productions are of the form α1 Aα2 → α1 βα2 with A ∈ VN ; α1 , α2 ∈ V ∗ , β ∈ VV ∗ (17) Exception: S → ε ∈ P is allowed if α1 , α2 ∈ (V \{S})∗ and β ∈ (V \{S})(V \{S})∗ (18) I If S → ε ∈ P, then S is not allowed in any right hand side I Consequence: Rules (almost) never derive shorter words 84 , The Chomsky hierarchy (2) G = hVN , VT , P, Si I (19) G is of Type 2 or context-free if all productions are of the form A → β with A ∈ VN ; β ∈ VV ∗ (20) S → ε ∈ P is allowed, if β ∈ (V \{S})(V \{S})∗ (21) Exception: 85 , The Chomsky hierarchy (2) G = hVN , VT , P, Si I (19) G is of Type 2 or context-free if all productions are of the form A → β with A ∈ VN ; β ∈ VV ∗ (20) S → ε ∈ P is allowed, if β ∈ (V \{S})(V \{S})∗ (21) Exception: I Only single non-terminals are replaced I If S → ε ∈ P, then S is not allowed in any right hand side 85 , The Chomsky hierarchy (3) G = hVN , VT , P, Si I (22) G is of Type 3 or right-linear (regular) if all productions are of the form A → aB or (23) A → a with A, B ∈ VN ; a ∈ VT Exception: S → ε ∈ P is allowed, if B ∈ VN \{S} (24) 86 , The Chomsky hierarchy: exercises G = hVN , VT , P, Si with 1. VN = {S, A, B}, 2. VT = {0}, 3. P : S S AB 0A A → → → → → ε ABA 00 000A 0 (25) 1 2 3 4 5 4. S = S. 87 , The Chomsky hierarchy: exercises G = hVN , VT , P, Si with 1. VN = {S, A, B}, 2. VT = {0}, 3. P : S S AB 0A A → → → → → ε ABA 00 000A 0 (25) 1 2 3 4 5 4. S = S. a) b) c) d) What is G ’s highest type? Show how G derives the word 00000. Formally describe the language L(G ). Define a regular grammar G 0 equivalent to G . 87 , The Chomsky hierarchy: exercises (cont.) An octal constant is a finite sequence of digits starting with 0 followed by at least one digit ranging from 0 to 7. Define a regular grammar encoding exactly the set of possible octal constants. 88 , Context-free grammars I Reminder: G = hVN , VT , P, Si is context-free, if all l → r ∈ P are of the form A → β with I A ∈ VN and β ∈ VV ∗ I (special case: S → ∈ P, then S is not allowed in any β) I Context-free languages/grammars are highly relevant I I I I Core of most programming languages Algebraic expressions XML Many aspects of human language 89 , Grammars in Practice I Most programming languages are described by context-free grammars (with extra “semantic” constraints) I Grammars generate languages I PDAs and e.g. CYK-Parsing recognize words For compiler we need to . . . I I identify correct programs I and understand their structure! 90 , Lexing and Parsing I Lexer: Breaks programs into tokens I I I I I I Smallest parts with semantic meaning Can be recognized by regular languages/patterns Example: 1, 2, 5 are all Integers Example: i, handle, stream are all Identifiers Example: >, >=, * are all individual operators Parser: Recognizes program structure I Language described by a grammar that has token types as terminals, not individual characters I Parser builds parse tree 91 , Introduction: nanoLang 92 , Our first language: nanoLang I I Simple but Turing-complete language Block-structured I Functions with parameters I Blocks of statements with local variables I Syntax C-like”but simplified I Basic flow control (if, while, return) I Simple static type system I Integers (64 bit signed) I Strings (immutable) 93 , nanoLang “Hello World” # The f i r s t e v e r nanoLang program I n t e g e r main ( ) { p r i n t ” H e l l o World \n” ; return 0; } 94 , More Substantial nanoLang Example I n t e g e r h e l l o ( I n t e g e r r e p e a t , S t r i n g message ) { Integer i ; i = 0; w h i l e ( i <r e p e a t ) { p r i n t message ; i = i +1; } return 0; } I n t e g e r main ( ) { h e l l o ( 1 0 , ” H e l l o \n” ) ; return 0; } 95 , nanoLang Lexical Structure I Reserved words: I if, while, return, print, Integer, String I I Comments: # to the end of the line Variable length tokens: I Identifier (letter, followed by letters and digits) I Strings (enclosed in double quotes (¨This is a string¨) I Integer numbers (non-empty sequences of digits) I Other tokens: I I I I I Brackets: (,), {,} Operators: +, -, *, / Comparison operators: >, >=, <, <=, != Equal sign = (used for comparison and assignments!) Separators: ,, ; 96 , nanoLang Program Structure I A nanoLang program consists of a number of definitions I Definitions can define global variables or functions I All symbols defined in the global scope are visible everywhere in the global scope I Functions accept arguments and return values I Functions consit of a header and a statement blocks I Local variables can be defined in statement blocks I Statements: I I I I I I I if: Bedingte Ausführung while: Schleifen return: Return value from function print: Print value to Screen Assignment: Set variables to values Function calls (return value ignored) Expressions: I Integers: Variables, numbers, +,-,*,/ I Booleans: Compare two values of equal type 97 , Exercise: Fibonacci in nanoLang I Write a recursive and an iterative implementation of Fibonacci numbers in nanoLang 98 , nanoLang Grammar (Bison format) (0 -tokens) %start prog %token %left %left %token %token %token OPENPAR CLOSEPAR MULT DIV PLUS MINUS EQ NEQ LT GT LEQ GEQ OPENCURLY CLOSECURLY SEMICOLON COMA %token %token %token %token %token <ident> IDENT <string> STRINGLIT <intval> INTLIT INTEGER STRING IF WHILE RETURN PRINT %token ERROR 99 , nanoLang Grammar (Bison format) (1) prog: /* Nothing */ | prog def ; def: vardef | fundef ; vardef: type IDENT SEMICOLON ; fundef: type IDENT OPENPAR params CLOSEPAR body ; type: STRING | INTEGER ; 100 , nanoLang Grammar (Bison format) (2) params: /* empty */ | paramlist ; paramlist: type IDENT | type IDENT COMA paramlist ; body: OPENCURLY vardefs stmts CLOSECURLY ; vardefs: /* empty */ | vardefs vardef ; stmts: /* empty */ | stmts stmt 101 , nanoLang Grammar (Bison format) (3) stmt: | | | | | ; while_stmt if_stmt ret_stmt print_stmt assign funcall_stmt while_stmt: WHILE OPENPAR boolexpr CLOSEPAR body ; if_stmt: IF OPENPAR boolexpr CLOSEPAR body ; ret_stmt: RETURN expr SEMICOLON ; 102 , nanoLang Grammar (Bison format) (4) print_stmt: PRINT expr SEMICOLON ; assign: IDENT EQ expr SEMICOLON ; funcall_stmt: funcall SEMICOLON ; boolexpr: | | | | | ; expr expr expr expr expr expr EQ expr NEQ expr LT expr GT expr LEQ expr GEQ expr 103 , nanoLang Grammar (Bison format) (5) expr: | | | | | | | | | ; funcall INTLIT IDENT STRINGLIT OPENPAR expr CLOSEPAR expr PLUS expr expr MINUS expr expr MULT expr expr DIV expr MINUS expr 104 , nanoLang Grammar (Bison format) (6) funcall: IDENT OPENPAR args CLOSEPAR ; args: /* empty */ | arglist ; arglist: expr |expr COMA arglist ; 105 , Exercise I Write a flex-based scanner for nanoLang I At minimum, it should output the program token by token I Bonus: Find a way to keep track of line numbers for tokens I Superbonus: Also keep track of columns I Reminder: Compiling flex programs: flex -t myflex.l > myflex.c gcc -o myflex myflex.c Example output for Hello World Integer = 277 main = 274 ( = 258 ) = 259 { = 270 print = 282 "Hello World\n" = 275 ; = 272 return = 281 0 = 276 ; = 272 } = 271 106 , Review: Goals for Today I I Refresher Reminder: Grammars and Chomsky-Hierarchy I Grammars I Regular languages and expressions I Context-free grammars and languages I Syntactic structure of programming languages I nanoLang I Programming exercise: Tokenizing nanoLang 107 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 108 , Goals for Today I I Refresher Syntax analysis revisited I The truth about Context-Free Grammars I Derivations and Parse Trees I Abstract Syntax Trees I Programming exercise: Parsing nanoLang 109 , Refresher I I Refresher Reminder: Grammars and Chomsky-Hierarchy I Grammars I Regular languages and expressions I Context-free grammars and languages I Syntactic structure of programming languages I nanoLang I Programming exercise: Tokenizing nanoLang 110 , The Truth about Context-Free Grammars (1) I Reminder: G is of Type 2 or context-free if all productions are of the form A → β with A ∈ VN ; β ∈ VV ∗ (26) S → ε ∈ P is allowed, if β ∈ (V \{S})(V \{S})∗ (27) Exception: I Only single non-terminals are replaced I If S → ε ∈ P, then S is not allowed in any right hand side 111 , The Truth about Context-Free Grammars (2) I Question: Is nanoLang context-free? 112 , The Truth about Context-Free Grammars (2) I Question: Is nanoLang context-free? I Question: Is the nanoLang grammar context-free? 112 , The Truth about Context-Free Grammars (2) I Question: Is nanoLang context-free? I Question: Is the nanoLang grammar context-free? Yes/No, but . . . 112 , The Truth about Context-Free Grammars (2) I Question: Is nanoLang context-free? I Question: Is the nanoLang grammar context-free? Yes/No, but . . . I Problem: prog: /* Nothing */ | prog def ; 112 , The Truth about Context-Free Grammars (2) I Question: Is nanoLang context-free? I Question: Is the nanoLang grammar context-free? Yes/No, but . . . I Problem: I prog: /* Nothing */ | prog def ; prog is the start symbol I prog → I prog → prog def 112 , The Truth about Context-Free Grammars (3) I Chomsky’s original definition: G is of Type 2 or context-free if all productions are of the form A → β with A ∈ VN ; β ∈ V ∗ (28) 113 , The Truth about Context-Free Grammars (3) I Chomsky’s original definition: G is of Type 2 or context-free if all productions are of the form A → β with A ∈ VN ; β ∈ V ∗ (28) Fact: Every Chomsky-CF-Grammar can be converted into a FLA-CF-Grammar! 113 , Exercise: Eliminating rules I Consider the following productions: 1. S → 2. S → A; S 3. A → i = n I Upper-case letters are non-terminals, S is the start symbol I Specify VN and VT I Create an equivalent FLA-CF-Grammar I Can you give a general method to convert Chomsky-CF-grammars to FLA-CF-gammars? 114 , A Running Example I We will consider the set of well-formed expressions over x, +, ∗.(, ) as an example, i.e. L(G ) for G as follows I I I I VN = {E } VT = {(, ), +, ∗, x} Start symbol is E Productions: 1. 2. 3. 4. E E E E →x → (E ) →E +E →E ∗E 115 , Derivations Definition: Assume a Grammar G . A derivation of a word wn in L(G ) is a sequence S =⇒ w1 =⇒ . . . =⇒ wn where S is the start symbol, and each wi is generated from its predecessor by application of a production of the grammar I Example: Consider our running example. We bold the replaced symbol. The following is a derivation of x + x + x ∗ x: =⇒ =⇒ =⇒ =⇒ =⇒ =⇒ =⇒ E E+E E +E +E E+E +E ∗E x +E+E ∗E x +x +E∗E x +x +x ∗E x +x +x ∗x 116 , Rightmost/Leftmost Derivations Definition: I A derivation is called a rightmost derivation, if at any step it replaces the rightmost non-terminal in the current word. I A derivation is called a leftmost derivation, if at any step it replaces the leftmost non-terminal in the current word. I Examples: I The derivation on the previous slide is neither leftmost nor rightmost. I E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x is a rightmost derivation. 117 , Parse trees Definition: A parse tree for a derivation in a grammar G = hVN , VT , P, Si is an ordered, labelled tree with the following properties: I Each node is labelled with a symbol from VN ∪ VT I The root of the tree is labelled with the start symbol S. I Each inner node is labelled with a single non-terminal symbol from VN I If an inner node with label A has children labelled with symbols α1 , . . . , αn , then there is a production A → α1 . . . αn in P. I The parse tree represents a derivation of the word formed by the labels of the leaf nodes It abstracts from the order in which productions are applied. I 118 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E n08 + E E + n09 n10 E 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * E 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * E x 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * x E x 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E x E * x E x 119 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E x E + E x E * x E x 119 , Ambiguity Definition: A grammar G = hVN , VT , P, Si is ambiguous, if it has multiple different parse trees for a word w in L(G ). I Consider our running example with the following productions: 1. 2. 3. 4. I E E E E →x → (E ) →E +E →E ∗E The following 2 parse trees represent derivations of x + x + x: E E E + E x E + x E E x x E + E + E x x 120 , Exercise: Ambiguity is worse. . . I Consider our example and the parse trees from the previous slide: 1. 2. 3. 4. E E E E →x → (E ) →E +E →E ∗E E E E + E x E + x E E x x I Provide a rightmost derivation for the right tree. I Provide a rightmost derivation for the left tree. I Provide a leftmost derivation for the left tree. I Provide a leftmost derivation for the right tree. E + E + E x x 121 , Exercise: Eliminating Ambiguity I Consider our running example with the following productions: 1. 2. 3. 4. I E E E E →x → (E ) →E +E →E ∗E Define a grammar G 0 with L(G ) = L(G 0 ) that is not ambiguous, that respects that ∗ has a higher precedence than +, and that respects left-associativity for all operators. 122 , Flex/Bison Interface I I Bison callse function yylex to get the next token yylex executes user rules (pattern/action) I User actions return token (integer value) I Additionally: yylval can be set and is available in Bison via the $$/$1/ldots mechanism I yylval provides the semantic value of a token I For complex languages: Use a pointer to a struct I Content: Position, string values, numerical values, . . . I Type of yylval if set in Bison file! %define api.value.type {YourType} 123 , Grading Exercise 2 I Write a Bison parser for nanoLang I Bonus: Translate nanoLang into Abstract Syntax Trees (will be required next week!) 124 , Review: Goals for Today I I Refresher Syntax analysis revisited I The truth about Context-Free Grammars I Derivations and Parse Trees I Abstract Syntax Trees 125 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 126 , Goals for Today I Refresher I Revisiting derivations, parse trees, abstract syntax trees I Walk-through: Parsing expressions in practice I Programming exercise: ASTs for nanoLang 127 , Refresher I I Refresher Syntax analysis revisited I The truth about Context-Free Grammars I Derivations and Parse Trees I Abstract Syntax Trees I Programming exercise: Parsing nanoLang (i.e. writing a program that accepts syntactically correct nanoLang programs and rejects syntactially incorrect ones (due next week) 128 , Parse trees Definition: A parse tree for a derivation in a grammar G = hVN , VT , P, Si is an ordered, labelled tree with the following properties: I Each node is labelled with a symbol from VN ∪ VT I The root of the tree is labelled with the start symbol S. I Each inner node is labelled with a single non-terminal symbol from VN I If an inner node with label A has children labelled with symbols α1 , . . . , αn , then there is a production A → α1 . . . αn in P. I The parse tree represents a derivation of the word formed by the labels of the leaf nodes It abstracts from the order in which productions are applied. I 129 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E n08 + E E + n09 n10 E 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * E 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * E x 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E E * x E x 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E E + E x E * x E x 130 , Parse trees: Example Consider the following derivation: E =⇒ E + E =⇒ E + E + E =⇒ E + E + E ∗ E =⇒ E + E + E ∗ x =⇒ E + E + x ∗ x =⇒ E + x + x ∗ x =⇒ x + x + x ∗ x It can be represented by a sequence of parse trees: E E + E x E + E x E * x E x 130 , Ambiguity Definition: A grammar G = hVN , VT , P, Si is ambiguous, if it has multiple different parse trees for a word w in L(G ). I Consider our running example with the following productions: 1. 2. 3. 4. I E E E E →x → (E ) →E +E →E ∗E The following 2 parse trees represent derivations of x + x + x: E E E + E x E + x E E x x E + E + E x x 131 , Exercise: Ambiguity is worse. . . I Consider our example and the parse trees from the previous slide: 1. 2. 3. 4. E E E E →x → (E ) →E +E →E ∗E E E E + E x E + x E E x x I Provide a rightmost derivation for the right tree. I Provide a rightmost derivation for the left tree. I Provide a leftmost derivation for the left tree. I Provide a leftmost derivation for the right tree. E + E + E x x 132 , Abstract Syntax Trees I Abstract Syntax Trees represent the structure of a derivation without the specific details I Think: “Parse trees without the syntactic sugar” I Example: Corresponding AST: Parse Tree: E + E + E + E x + E x x x x x 133 , From text to AST in practice: Parsing nanoLang expressions I Example for syntax analysis and building abstract syntax trees I Language: nanoLang expressions (without function calls) I Structure of the project I Building I Code walk-through 134 , Exercise: Building exprcc I I I I Go to http://wwwlehre.dhbw-stuttgart.de/~sschulz/cb2015.html Download NANOEXPR.tgz Unpack, build and test the code To test: I ./exprcc expr1.nano I ./exprcc --sexpr expr1.nano I ./exprcc --dot expr1.nano 135 , exprcc Overview AST definitions ast.h #include flex/bison gcc Parser specification nanoparse.y linker Parser defs nanoparse.tab.h Lexer specification nanolex.l Lexer implementation nanolex.c Parser impl. nanoparse.tab.c AST implementation ast.c Lexer object file nanolex.o Parser object file nanoparse.tab.c AST object file ast.o Executable: exprcc 136 , exprcc Makefile 137 , A first Abstract Syntax Tree I Test expression: -a+b*(c+d) I Corresponding AST? 138 , A first Abstract Syntax Tree I Test expression: -a+b*(c+d) I Corresponding AST? t_PLUS t_MINUS t_MULT t_IDENT a t_IDENT b t_IDENT c t_PLUS t_IDENT d 138 , Simplified nanoLang expression syntax expr: | | | | | | | | ; INTLIT IDENT STRINGLIT OPENPAR expr CLOSEPAR expr PLUS expr expr MINUS expr expr MULT expr expr DIV expr MINUS expr 139 , Alternative notation expr -> INTLIT | IDENT | STRINGLIT | ( expr ) | expr + expr | expr - expr | expr * expr | expr / expr | - expr 140 , Alternative notation expr -> INTLIT | IDENT | STRINGLIT | ( expr ) | expr + expr | expr - expr | expr * expr | expr / expr | - expr Question: Is the grammar unambiguous? 140 , Alternative notation expr -> INTLIT | IDENT | STRINGLIT | ( expr ) | expr + expr | expr - expr | expr * expr | expr / expr | - expr Question: Is the grammar unambiguous? I How do we solve this? 140 , Precedences and Associativity in Bison I Code: nanoparse.y token definitions I The trick with unary - 141 , Implementing ASTs I Code: ast.c, ast.h 142 , Lexical Analysis I Code: nanolex.l 143 , Building ASTs I Code: nanoparse.y syntax rules and semantic actions 144 , Grading Exercise 3 I Extend the nanoLang parser to generate abstract syntax trees nanoLang programs I You can use your own parser or extend the expression parser from this lecture I Due date: Our lecture on April 22nd 145 , Review: Goals for Today I Refresher I Revisiting derivations, parse trees, abstract syntax trees I Walk-through: Parsing expressions in practice I Programming exercise: ASTs for nanoLang 146 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 147 , Goals for Today I I Refresher Semantic properties I Names, variables, identifiers I Visibility and scopes I Simple types and type systems I Symbol tables I Memory organisation and storage locations 148 , Refresher I Formal definition of parse trees I Ambiguity and derivation types I Abstract syntax trees Syntax analysis in practice I I nanoLang expression parser I Abstract syntax tree datatype and algorithms I Parsing nanoLang expressions with Bison I Programming exercise: Parsing nanoLang into abstract syntax trees 149 , High-Level Architecture of a Compiler Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 150 , High-Level Architecture of a Compiler Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 150 , High-Level Architecture of a Compiler Flex Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 150 , High-Level Architecture of a Compiler Flex Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Bison Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 150 , High-Level Architecture of a Compiler Flex Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Bison Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree C Code ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 150 , Semantic Constraints 151 , Group Exercise: Spot the Bugs (1) I n t e g e r fun1 ( I n t e g e r i , I n t e g e r i ) { Integer i ; i f ( i > 0) { print j ; } } I n t e g e r main ( ) { fun1 (1 , 2 ) ; fun2 (1 , 2 ) ; return 0; } 152 , Group Exercise: Spot the Bugs (2) I n t e g e r fun1 ( I n t e g e r i , I n t e g e r j ) { Integer i ; i f ( i > ”0” ) { p r i n t j+” 12 ” ; } return 1; } I n t e g e r main ( ) { fun1 (1 , ” Hello ” ) ; fun2 (1 , 2 , 3 ) ; return 0; } 153 , Group Exercise: Spot the Bugs (3) I n t e g e r fun1 ( I n t e g e r i , I n t e g e r j ) { w h i l e ( j >i ) { Integer j ; print j ; j=j +1; } return 1; } 154 , Semantic constraints of nanoLang (V 1.0) I Every name has to be defined before it can be used I Every name can only be defined once in a given scope I Functions must be called with arguments of the right type in the right order I Operands of comparison operators must be of the same type I Operands of the arithmetic operators must be of type Integer I Every program must have a main() I (Every function must have a return of proper type) 155 , Managing Symbols I Properties of identifiers are stored in a symbol table I Name I Type I Properties of identifiers depend on part of the program under consideration! I Names are only visible in the scope they are declared in I Names can be redefined in new scopes 156 , Managing Symbols I Properties of identifiers are stored in a symbol table I Name I Type I Properties of identifiers depend on part of the program under consideration! I Names are only visible in the scope they are declared in I Names can be redefined in new scopes Symbol tables need to change when traversing the program/AST for checking properties and generating code! 156 , Names and Variables I Definition: A variable is a location in memory (or “in the store”) that can store a value (of a given type) I Variables can be statically or dynamically allocated I I I I Typically: global variables are statically allocated (and in the data segment of the process Local variables are dynamically managed and on the stack Large data structures and objects are stored in the heap Definition: A name is an identifier that identifies a variable (in a given scope) I The same name can refer to different variables (recursive function calls) I Different names can refer to the same variables (depends on programming languages - aliasing 157 , Scopes and Environments I I The environment establishes a mapping from names to variables Static scope: Environment depends on block structure of the language I In any situation, the name refers to the variable defined in the neares surrounding block in the program text I Examples: C (mostly), Pascal, Java, modern LISPs (mostly) I Dynamic scope: Environment depends on calling sequence in program I Name refers to the same variable it referred to in the calling function I Traditional LISP systems (Emacs LISP) 158 , Group exercise: Static and dynamic scopes #i n c l u d e <s t d i o . h> i n t a =10; i n t b =10; #d e f i n e a d d e r ( x ) ( x)+a v o i d machwas ( i n t a , i n t c ) { p r i n t f ( ” a d d e r ( a)=%d\n” , a d d e r ( a ) ) ; p r i n t f ( ” a d d e r ( b)=%d\n” , a d d e r ( b ) ) ; p r i n t f ( ” a d d e r ( c)=%d\n” , a d d e r ( c ) ) ; { int c = 5; p r i n t f ( ” a d d e r ( c)=%d\n” , a d d e r ( c ) ) ; } } i n t main ( v o i d ) { machwas ( 1 , 2 ) ; machwas ( 2 , 3 ) ; return 0; } 159 , Example: Scopes in nanoLang Integer i ; I n t e g e r fun1 ( I n t e g e r loop ) { Integer i ; i =0; w h i l e ( i <l o o p ) { i=i +1; print ” Hallo ” ; } } I n t e g e r main ( ) { i = 5; fun1 ( i ) ; } 160 , Scopes in nanoLang I Global scope I Global variables I Functions I Function scope I Function parameters I Block scope I block-local variables 161 , Example: Scopes in nanoLang Integer i ; I n t e g e r fun1 ( I n t e g e r loop ) { Integer i ; i =0; w h i l e ( i <l o o p ) { i=i +1; print ” Hallo ” ; } } I n t e g e r main ( ) { i = 5; fun1 ( i ) ; } 162 , Walking the AST prog prog prog vardef t_INTEGER t_IDENT i t_INTEGER fundef fundef t_INTEGER t_IDENT fun1 param t_IDENT loop t_INTEGER t_IDENT main t_INTEGER params params body body stmts vardef stmts t_IDENT i assign while_stmt t_INTLIT 0 t_LT t_IDENT i assign t_IDENT i t_IDENT i t_IDENT i stmts assign t_IDENT i t_IDENT fun1 body t_IDENT loop t_IDENT i t_INTLIT 5 funcall t_PLUS print_stmt Hallo t_INTLIT 1 163 , Static type checking I Types are associated with variables I Types are checked at compile time or development time Advantages: I I ? I Disadvantages: I ? I Typically used in: I ? 164 , Dynamic type checking I Types are associated with values I Types are checked at run time Advantages: I I ? I Disadvantages: I ? I Typically used in: I ? 165 , No type checking I Programmer is supposed to know what (s)he does I Types are not checked at all Advantages: I I ? I Disadvantages: I ? I Typically used in: I ? 166 , Exercise: How many types occur in this example? Integer i ; I n t e g e r fun1 ( I n t e g e r loop ) { Integer i ; i =0; w h i l e ( i <l o o p ) { i=i +1; print ” Hallo ” ; } } I n t e g e r main ( ) { i = 5; fun1 ( i ) ; } 167 , Symbol tables I I Store name (identifier) and type Nested for each scope: I Global scope I Each new scope entered will result in a new symbol table for that scope, pointing to the preceeding (larger scope) I Local operations: I Global operations: I Add name/type (error if already defined) I Find name (finds “nearest” matching entry, or error) I Enter new scope (creates a new empty symbol table pointing to the predecessor (if any) I Leave scope (remove current scope) 168 , Walking the AST prog prog prog vardef t_INTEGER t_IDENT i t_INTEGER fundef fundef t_INTEGER t_IDENT fun1 param t_IDENT loop t_INTEGER t_IDENT main t_INTEGER params params body body stmts vardef stmts t_IDENT i assign while_stmt t_INTLIT 0 t_LT t_IDENT i assign t_IDENT i t_IDENT i t_IDENT i stmts assign t_IDENT i t_IDENT fun1 body t_IDENT loop t_IDENT i t_INTLIT 5 funcall t_PLUS print_stmt Hallo t_INTLIT 1 169 , Walking the AST prog prog prog vardef t_INTEGER t_IDENT i t_INTEGER fundef fundef t_INTEGER t_IDENT fun1 param t_IDENT loop t_INTEGER t_IDENT main t_INTEGER params params body body stmts vardef stmts t_IDENT i assign while_stmt t_INTLIT 0 t_LT t_IDENT i assign t_IDENT i t_IDENT i t_IDENT i stmts assign t_IDENT i t_IDENT fun1 body t_IDENT loop t_IDENT i t_INTLIT 5 funcall t_PLUS print_stmt Hallo t_INTLIT 1 169 , Representing types I Types table: I Numerical encoding for each type I Recipe for each type I I I nanoLang basic types are atomic Atomic types can also be addressed by name Function types are vectors of existing types Encoding 0 I E.g. 1 2 I Type String Integer Integer fun(Integer, String) Recipe atomic atomic (1, 1, 0) Operations: I Find-or-insert type I I Return encoding for a new type If type does not exist yet, create it 170 , Programming Exercise I Develop data structures for representing nanoLang types I Develop data structures for implementing nested symbol tables 171 , Review: Goals for Today I I Refresher Semantic properties I Names, variables, identifiers I Visibility and scopes I Simple types and type systems I Symbol tables I Memory organisation and storage locations 172 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 173 , Goals for Today I Refresher I Symbol Tables in practice I Type inference and type checking I Exercise: Build symbol tables 174 , Refresher I Semantic properties I Names, variables, identifiers I Visibility and scopes I Simple types and type systems I Symbol tables I Memory organisation and storage locations 175 , The Big Picture: Type Checking I We need to know the type of every expression and variable in the program I . . . to detect semantic inconsistencies I . . . to generate code I Some types are simple in nanoLang I String constants are type String I Integer constants are type Integer I Results of arithmetic operations are Integer I Harder: What to do with identifiers? I Type of the return value of a function? I Types of the arguments of a function? I Types of the values of a variable? 176 , The Big Picture: Type Checking I We need to know the type of every expression and variable in the program I . . . to detect semantic inconsistencies I . . . to generate code I Some types are simple in nanoLang I String constants are type String I Integer constants are type Integer I Results of arithmetic operations are Integer I Harder: What to do with identifiers? I Type of the return value of a function? I Types of the arguments of a function? I Types of the values of a variable? The answers depend on the definitions in the program! 176 , Symbol Tables I I Symbol tables associate identifiers and types Symbol tables form a hierarchy I Symbols can be redefined in every new context I The “innermost” definition is valid I Symbol tables are filled top-down I Outermost symbol-table contains global definitions I Each new context adds a new layer I Search for a name is from innermost to outermost symbol table 177 , Building Symbol Tables Program Symbol table Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Symbol table Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i Integer Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i Integer Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i Integer - - Integer main() { i = 5; fun1(i); } 178 , Building Symbol Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } Symbol table i Integer fun1 (Integer)→Integer main ()→Integer loop Integer i Integer - - i Integer fun1 (Integer)→Integer main ()→Integer - - - - 178 , Simplified Type Handling I I Handling complex types directly is cumbersome Better: Manage types separately I Types are stored in a separate table I Symbol table only needs to handle indices into type table 179 , Symbol Tables and Type Tables Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } Symbol table Type table i 1 1 Integer fun1 2 2 (Integer)→Integer main 3 loop 1 3 ()→Integer i 1 - - i 1 fun1 2 main 3 - - 180 , Type Inference in nanoLang I I Goal: Determine the (result) type of every expression in the program Process: Process AST bottom-up I Constants: “natural” type I Variables: Look up in symbol table I Function calls: Look up in symbol table I I If arguments are not of proper type, error Otherwise: return type of the function I Arithmetic expressions: I I If arguments are Integer, result type is Integer Otherwise: error 181 , Contrast: Aspects of Type Inference in C I Arithmetic expressions: I Roughly: arithmetic types are ordered by size (char < int < long < long long < float < double) I Type of a + b is the greater of the types of a and b I Arrays I Pointers I If a is an array of int, than a[1] is of type int I If a is of type char*, then *a is of type char I Many more cases: I Structures I Enumerations I Function pointers 182 , Symbol Tables and the AST prog prog prog vardef t_INTEGER t_INTEGER Program Integer i; Integer fun1(Integer loop) { Integer i; } i=0; while(i<loop) { i=i+1; print "Hallo"; } Integer main() { i = 5; fun1(i); } fundef t_IDENT fun1 t_INTEGER t_IDENT i fundef params t_INTEGER Symbol table i params body body param t_IDENT loop t_IDENT main t_INTEGER stmts vardef stmts t_IDENT i assign while_stmt t_INTLIT 0 t_LT t_IDENT i assign t_IDENT i t_INTLIT 5 funcall t_IDENT fun1 t_IDENT i body Integer fun1 (Integer)→Integer main ()→Integer t_IDENT i t_IDENT loop stmts loop Integer i Integer - - assign t_IDENT i i Integer fun1 (Integer)→Integer t_IDENT i t_PLUS print_stmt Hallo t_INTLIT 1 main ()→Integer - - - - 183 , Implementation Examples I main() in nanoparse.y I STBuildAllTables() in semantic.c I symbols.h and symbols.c I types.h and types.c 184 , Grading Exercise 4 Extend your compiler project by computing the relevant symbol tables for all nodes of your AST I Develop a type table date type for managing different types I Define a symbol table data type for managing symbols and their types I Use a hierarchical structure I Suggested operations: I I I I I EnterScope() LeaveScope() InserSymbol() (with type) FindSymbol() (return entry including type) ... Traverse the AST in a top-down fashion, computing the valid symbol table at each node I Annotate each AST node with the symbol table valid at that node At the end, print all symbols and types of the global, top-level symbol table! I 185 , Example Output > ncc NANOEXAMPLES/scopes.nano Global symbols: --------------i : Integer fun1 : (Integer) -> Integer main : () -> Integer Types: -----0: NoType 1: String 2: Integer 3: (Integer) -> Integer 4: () -> Integer 186 , Review: Goals for Today I Symbol Tables in practice I Type inference and type checking I Exercise: Build symbol tables 187 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 188 , Goals for Today I Refresher I Excursion: assert() in C Code generation considerations I I I I I I I Parameter passing Assignments Calling conventions Runtime support Libraries nanoLang runtime I Parameter passing I nanoLang string semantics I nanoLang library functions and OS interaction I Exercise: Type checking 189 , Refresher I Symbol Tables in practice (top-down traversal) I Type inference and type checking (bottom-up traversal) I Example code walk-through I Exercise: Build symbol tables 190 , Excursion: assert() I assert() is a facility to help debug programs I Part of the C Standard since C89 I To use, #include <assert.h> I assert(expr) evaluates expr I If expr is false, then an error message is written and the program is aborted I Otherwise, nothing is done I Hints: I Particularly useful to check function parameter values I To disable at compile time, define the macro NDEBUG (e.g. with the compiler option -DNDEBUG I Useful idiom: assert(expr && "What’s wrong"); I More information: man assert 191 , Semantics of Compiled and Target Language I I Before we can compile a language, we must understand its semantics Important questions: I How are parameter passed into functions? I Related: How do assignments work? I Before we can compile a language, we must understand the target language and environment I How are parameters and local variables handled? I How does the program interact with the OS and the environment? 192 , Parameter Passing I Call by value I Formal parameters become new local variables I Actual parameters are evaluated and used to initialize those variables I Changes to variables are irrelevant after function terminates I Call by reference I Only references to existing variables are passed I In effect, formal parameters are bound to existing variables I Actual parameters that are not variables themselves are evaluated and placed in anonymous new variables I Changes to paramters in functions change the original variable I Call by name I Only historically interesting I Semantics mostly similar to call-by-value 193 , Parameter Passing - Advantages and Disadvantages? I I Call by value? Call by reference? 194 , Parameter Passing - Advantages and Disadvantages? I I I Call by value? Call by reference? For your consideration: int fun ( int a , int b) { a++; b++; r e t u r n a+b ; } i n t main ( v o i d ) { i n t i =0; fun ( i , i ) ; p r i n t f ( ” i=%d\n” , i ) ; } 194 , Parameter Passing in C/C++/Pascal/Scheme? I C? I C++? I Pascal? I LISP/Scheme? I Others? 195 , Assignments I What happens if a = b; is encountered? I I I I If If If If both both both both are integer variables? are string variables? have an object type? are arrays? 196 , Calling conventions I How are paramters values passed at a low level? I Registers? I Stack? I Other? I Who is responsible for preserving registers? I Caller? I Callee? I In which order are parameters passed? I How is the old context (stack frame and PC) preserved and restored? 197 , Calling conventions I How are paramters values passed at a low level? I Registers? I Stack? I Other? I Who is responsible for preserving registers? I Caller? I Callee? I In which order are parameters passed? I How is the old context (stack frame and PC) preserved and restored? For our nanoLang compiler, we rely on C to handle these things! 197 , Runtime system and OS Integration I Runtime system provides the glue between OS and program I Runtime system provides execution support for program semantics I Translates OS semantics/conventions to compiled language and back I Higher-level functions/data types I Memory management I Library functions 198 , Parameter passing and assignments in nanoLang I Suggestion: All parameter passed “as if” by value I Integer: Pass by value Immutable strings I I Can be passed by reference I Need to be memory-managed (reference counting, a job for the runtime system) I Alternative is not simpler! 199 , nanoLang OS integration I Command line arguments I Suggestion: main() takes arbitrary number of string arguments I These are filled from the command line I Spare arguments are represented by the empty string I Exit and return value I Library function Exit(val) terminates program and returns integer value I return from main() has the same effect 200 , nanoLang Library Functions I Suggested function to make things interesting: I StrIsInt(str): Returns 1 if str encodes a valid integer, 0 otherwise I StrToInt(): Converts a string to an integer. If str is not an integer encoding, result is undefined I IntToStr(int): Returns a string encoding of the given integer I StrLength(str): Returns the lengths of str I More sugegstions? I String StrFront(str, int) - return first int characters as new string I String StrRest(str, int) - return all but first int characters I String StrCat(str, str) - concatenate strings, return as new string I Integer StrToASCII(str) - only for strings of lenght 1, return ASCII value I String ASCIIToStr(int) - reverse of the above 201 , nanoLang Strings I Temptation: Use C char* I Fails as soon as strings can be dynamically created Suggestion: Structure with reference counting I I String value - the actual string (malloc()ed char*) I Length (maybe) I Reference count - how many places have a reference to the string? I I I Increase if string is assigned to a variable or passed to a function Decrease, if a variable is reassigned or goes out of scope Free string, if this reaches 0 202 , Grading Exercise 5 Extend your compiler project by computing the types of all expressions in your system and check type constraints I Check that variables are only assigned values of the right type I Check that functions are only called with correctly typed parameters I Check that operators have compatible types I Check that comparisons only happen between expressions of the same type I Bonus: Check that functions (always) return the correct type 203 , Review: Goals for Today I I Excursion: assert() in C Code generation considerations I I I I I I Parameter passing Assignments Calling conventions Runtime support Libraries nanoLang runtime I Parameter passing I nanoLang string semantics I nanoLang library functions and OS interaction 204 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 205 , Goals for Today I Refresher I Coding Hints I Code generation nanoLang to C I (Simple) Optimizations I Exercise: Code generation (I) 206 , Refresher I I assert() General considerations for code generation I Semantics of parameters/assignments I Function calls I Runtime support and libraries I Special considerations for nanoLang I Strings I Command line processing I Built-in library functions 207 , Coding hints I The nanoLang compiler is a non-trivial piece of software I Several modules I Several different data types (AST, Types, Symbols) I It helps to follow good coding practices I The big stuff: Good code structure I I One function per function Not more than one screen page per function I The small stuff I I I I I Clean formatting (including vertical space) Use expressive names for functions and variables Reasonable comments (don’t over-comment, though!) Use assert() Compile with warnings enables (Makefile: CFLAGS = -Wall) 208 , The Final Phase Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 209 , The Final Phase Source handler Sequence of characters: i,n,t, ⏘, a,,, b, ;, a, =, b, +, 1, ; Lexical analysis (tokeniser) Sequence of tokens: (id, “int”), (id, “a”), (id, “b”), (semicolon), (id, “a”), (eq), (id, “b”), (plus), (int, “1”), (semicolon) Syntactic analysis (parser) ���� ���� e.g. Abstract syntax tree ����� ���� ��� ���� ���������� ��� � ��� � ��� � � ��� � Semantic analysis ��� � ���� ����� e.g. AST+symbol table+attributes ���������� ��� � Code generation (several optimisation passes) e.g. assembler code � ��� � Variable Type a int b int ��� � ld a,b ld c, 1 add c ... 209 , Code Generation nanoLang to C I Suggestion: Code generation uses separate phases I I I I I I Initial boilerplate Global variable definitions Function declarations Constant library code Translation of function definitions C main() function 210 , Name Mangling I I To avoid name conflicts, nanoLang identifer should use a standard naming scheme Suggestion: I Atomic type names are prepended with N I Function and variable names are prepended with n 211 , Initial boilerplate I Emit constant code needed for each translated nanoLang program I I I I I Comment header Standard system includes Type definitions Possibly macro definitions Implementation via printing constant string I Easiest way I Alternative: Read from file 212 , Global variable definitions I Visibility difference between nanoLang and C I Globally defined nanoLang identifiers are visible throughout the program I C definitions are visible from the point of definition only I Hence we need to declare variables (and functions) upfront I Implementation suggestion: I Iterate over all symbols in the global symbol table I For each variable symbol, emit a declaration 213 , Function declarations I The same visibility difference between nanoLang and C affects functions I We need to declare all functions upfront! I Implementation suggestion: I Iterate over all symbols in the global symbol table I For each function symbol, emit a declaration 214 , Function declarations I The same visibility difference between nanoLang and C affects functions I We need to declare all functions upfront! I Implementation suggestion: I Iterate over all symbols in the global symbol table I For each function symbol, emit a declaration Suggestion: For simplicity and consistency, we should insert the nanoLang standard library functions (Exit(), StrIsInt(), StrToInt, . . . ) into the symbol table (and do so before semantic analysis to stop the user from inadvertently redefining them!) 214 , Constant library code I The nanoLang runtime will need various pieces of code I Data types and helper functions to handle e.g. Strings I Implementations of the build-in functions I Implementation options I I I I Just insert plain C code here (Alternative 0, but this may be lengthy) Alternative 1: Read this C code from a file Alternative 2: Just #include the full C code Alternative 3: #include only header with declarations, then require linking with a run time library later 215 , Translation of function definitions I I This is the heart of the compiler! Go over the AST and emit a definition for each function nanoLang functions become C functions Local nanoLang variables become C variables of an appropriate type nanoLang blocks become C blocks nanoLang instructions are translated into equivalent C statement sequences I Mostly straightforward I I I I I I print requires case distinction String comparisions require library calls 216 , Translation of function definitions I I This is the heart of the compiler! Go over the AST and emit a definition for each function nanoLang functions become C functions Local nanoLang variables become C variables of an appropriate type nanoLang blocks become C blocks nanoLang instructions are translated into equivalent C statement sequences I Mostly straightforward I I I I I I print requires case distinction String comparisions require library calls More complex: Proper string handling 216 , C main() function I I Generate an appropriate main() function Tasks: I Read commandline and initialize parameters for nanoLang main() I Call nanoLang main I Exit program, returning value from nanoLang main() to OS 217 , Ideas for optimization I I Constant subexpression evaluation Common subexpression elimination I To do this well, we need to identify pure functions! I Shift unneeded computations out of loop I Eliminate computations of unused values w h i l e ( i <10) { a = 3∗10∗ i ; b = 3∗10∗ f u n ( a ) ; i=i +1; } return a ; 218 , Grading Exercise 6 Extend your compiler project to generate a basic C programm I Compile nanoLang statements into equivalent C statements I Compile nanoLang definitions into C declarations and definitions I Generate a basic main() I For now, you can treat String as an imutable char* - we’ll do the library next week 219 , Review: Goals for Today I Refresher I Coding Hints I Code generation nanoLang to C I Optimizations I Exercise: Code generation (I) 220 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 221 , Goals for Today I Refresher I Practical aspects of nanoLang code generation I An introduction to top-down recursive descent parsing 222 , Refresher I I Coding Hints Code generation nanoLang to C I I I I I I Name handling Global definitions Libraries Functions ... Optimizations I I I I I Constant subexpressions Common subexpressions (purely functional functions!) Lift invariant expression out of loops Eliminate computation of unused results ... 223 , Practical code generation for nanoLang 224 , nanoLang C premable (1) /∗ ∗ A u t o m a t i c a l l y g e n e r a t e d by t h e nanoLang c o m p i l e r n c c . ∗ ∗ The b o l i e r p l a t e and l i b r a r y c o d e i s r e l e a s e d u n d e r t h e GNU G e n e r a l P u b l i c ∗ L i c e n c e , v e r s i o n 2 or , a t y o u r c h o i c e , any l a t e r v e r s i o n . Other code i s ∗ g o v e r n e d by t h e l i c e n s e o f t h e o r i g i n a l s o u r c e c o d e . ∗/ #i n c l u d e <s t d i o . h> #i n c l u d e <s t d l i b . h> #i n c l u d e <s t r i n g . h> typedef long long N Integer ; typedef char ∗N String ; #d e f i n e NANO MAKESTR( s ) s #d e f i n e NANO STRASSIGN ( l , r ) ( l ) = ( r ) #d e f i n e NANO STRVAL( s ) s /∗ G l o b a l u s e r v a r i a b l e s ∗/ 225 , nanoLang C premable (2) /∗ F u n c t i o n d e c l a r a t i o n s ∗/ N N N N N N N N N N N N Integer Integer Integer Integer String String String String Integer String String Integer n n n n n n n n n n n n Exit ( N Integer ); S t r I s I n t ( N String ) ; StrToInt ( N String ) ; StrLen ( N String ) ; IntToStr ( N Integer ); StrFront ( N String , N Integer ) ; StrRest ( N String , N Integer ) ; StrCat ( N String , N String ) ; StrToASCII ( N String ) ; ASCIIToStr ( N Integer ) ; testfun ( N Integer , N String ) ; main ( N String , N S t r i n g ) ; /∗ nanoLang r u n t i m e l i b r a r y c o d e ∗/ /∗ S t r i n g f u n c t i o n s ∗/ N String n S t r C a t ( N S t r i n g arg1 , N S t r i n g arg2 ) { l e n = s t r l e n ( arg1 ) + s t r l e n ( arg2 ) + 1; size t char ∗res = malloc ( len ) ; s t r c p y ( res , arg1 ) ; s t r c a t ( res , arg2 ) ; return res ; } [...] 226 , nanoLang and its translation (2) S t r i n g t e s t f u n ( I n t e g e r co un t , S t r i n g message ) { Integer i ; String res ; i =0; r e s=” ” ; w h i l e ( i<c o u n t ) { print ”Schleifendurchlauf ”; print i ; p r i n t ”\n” ; r e s = StrCat ( r e s , message ) ; i=i +1; } return res ; } N String n t e s t f u n ( N I n t e g e r n count , N String n message ) { N Integer n i = 0; N String n res = 0; n i = (0); NANO STRASSIGN ( n r e s , (NANO MAKESTR( ” ” ) ) ) ; n r e s = (NANO MAKESTR( ” ” ) ) ; while (( n i ) < ( n count )) { p r i n t f ( ”%s ” , NANO STRVAL ( ( NANO MAKESTR( ” S c h l e i f e n d u r c h l a u f ” ) ) ) ) ; p r i n t f ( ”%l l d ” , ( n i ) ) ; p r i n t f ( ”%s ” , NANO STRVAL ( (NANO MAKESTR( ”\n” ) ) ) ) ; NANO STRASSIGN ( n r e s , ( n S t r C a t ( ( n r e s ) , ( n message ) ) ) ) ; n r e s = ( n StrCat (( n r e s ) , ( n message ) ) ) ; n i = (( n i ) + (1)); } return ( n res ); } 227 , nanoLang and its translation (2) I n t e g e r main ( S t r i n g a r g 1 , S t r i n g arg2 ) N I n t e g e r n main ( N S t r i n g n arg1 , N String n arg2 ) { { N Integer n limit = 0; n limit = (10); i f ( ( n S t r I s I n t ( ( n a r g 1 ) ) ) == ( 1 ) ) { n l i m i t = ( n StrToInt (( n arg1 ) ) ) ; } p r i n t f ( ”%s ” , NANO STRVAL ( ( n t e s t f u n ( ( n l i m i t ) , ( n arg2 ) ) ) ) ) ; p r i n t f ( ”%s ” , NANO STRVAL ( (NANO MAKESTR( ”\n” ) ) ) ) ; return (0); Integer limit ; l i m i t = 10; i f ( S t r I s I n t ( a r g 1 )=1) { l i m i t =S t r T o I n t ( a r g 1 ) ; } p r i n t t e s t f u n ( l i m i t , arg2 ) ; p r i n t ”\n” ; } return 0; } 228 , nanoLang C main /∗ C main f u n c t i o n ∗/ i n t main ( i n t a r g c , c h a r ∗ a r g v [ ] ) { N S t r i n g a r g 1 = NANO MAKESTR( ” ” ) ; i f (1 < argc ) { a r g 1 = NANO MAKESTR( a r g v [ 1 ] ) ; } N S t r i n g a r g 2 = NANO MAKESTR( ” ” ) ; i f (2 < argc ) { a r g 2 = NANO MAKESTR( a r g v [ 2 ] ) ; } n m a i n ( arg1 , a r g 2 ) ; } 229 , Top-Down Parsing 230 , Basic Idea of Recursive Descent I One parsing function per non-terminal I Initial function corresponds to start symbol Each function: I I Uses an oracle to pick the correct production I Processes the right hand side against the input as follows: I I If the next symbol is a terminal, it consumes that terminal from the input (if it’s not in the input: error) If the next symbol is a non-terminal, it calls the corresponding function 231 , Basic Idea of Recursive Descent I One parsing function per non-terminal I Initial function corresponds to start symbol Each function: I I Uses an oracle to pick the correct production I Processes the right hand side against the input as follows: I I If the next symbol is a terminal, it consumes that terminal from the input (if it’s not in the input: error) If the next symbol is a non-terminal, it calls the corresponding function Oracle: Based on next character to be read! I Good case: Every production can be clearly identified 231 , Basic Idea of Recursive Descent I One parsing function per non-terminal I Initial function corresponds to start symbol Each function: I I Uses an oracle to pick the correct production I Processes the right hand side against the input as follows: I I If the next symbol is a terminal, it consumes that terminal from the input (if it’s not in the input: error) If the next symbol is a non-terminal, it calls the corresponding function Oracle: Based on next character to be read! I Good case: Every production can be clearly identified I Bad case: Common initial parts of right hand sides =⇒ ? 231 , Example/Exercise I Consider the following productions from G1 : I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? 232 , Example/Exercise I Consider the following productions from G1 : I I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? What happens if we use the following productions from G2 ? I S → aSb I S → ab 232 , Example/Exercise I Consider the following productions from G1 : I I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? What happens if we use the following productions from G2 ? I S → aSb I S → ab I Productions in G2 have common prefixes 232 , Example/Exercise I Consider the following productions from G1 : I I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? What happens if we use the following productions from G2 ? I S → aSb I S → ab I Productions in G2 have common prefixes I Common prefixes make the oracle work hard(er) I How can we get G1 from G2 ? 232 , Example/Exercise I Consider the following productions from G1 : I I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? What happens if we use the following productions from G2 ? I S → aSb I S → ab I Productions in G2 have common prefixes I Common prefixes make the oracle work hard(er) I How can we get G1 from G2 ? Left factoring! 232 , Example/Exercise I Consider the following productions from G1 : I I I I I I I S → aA A → Bb B → aA B→ What is the language produced? How can we parse aabb? What happens if we use the following productions from G2 ? I S → aSb I S → ab I Productions in G2 have common prefixes I Common prefixes make the oracle work hard(er) I How can we get G1 from G2 ? Left factoring! Plus. . . 232 , Left recursion Definition: A grammar G = hVN , VT , P, Si is left-recursive, if there + exist A ∈ VN , w ∈ (VN ∪ VT )∗ with A =⇒ Aw . 233 , Left recursion Definition: A grammar G = hVN , VT , P, Si is left-recursive, if there + exist A ∈ VN , w ∈ (VN ∪ VT )∗ with A =⇒ Aw . I Left recursion leads to infinite loops in recursive descent parsers I To parse A, we first need to parse A . . . I Solution: Reformulate grammar 233 , Our Running Example I We will again consider the set of well-formed expressions over x, +, ∗.(, ) as an example, i.e. L(G ) for G as follows I I I I VN = {E } VT = {(, ), +, ∗, x} Start symbol is E Productions: 1. 2. 3. 4. E E E E →x → (E ) →E +E →E ∗E 234 , Our Running Example (unambiguous) I We will again consider the set of well-formed expressions over x, +, ∗.(, ) as an example, i.e. L(G ) for G as follows I I I I VN = {E , T , F } VT = {(, ), +, ∗, x} Start symbol is E Productions: 1. 2. 3. 4. 5. 6. E E T T F F →E +T →T →T ∗F →F → (E ) →x 235 , Our Running Example (unambiguous) I We will again consider the set of well-formed expressions over x, +, ∗.(, ) as an example, i.e. L(G ) for G as follows I I I I VN = {E , T , F } VT = {(, ), +, ∗, x} Start symbol is E Productions: 1. 2. 3. 4. 5. 6. E E T T F F →E +T →T →T ∗F →F → (E ) →x What happens if we want to parse this using recursive descent? 235 , Exercise: Recursive Descent for Expressions I Consider the following productions: 1. 2. 3. 4. 5. 6. E E T T F F →E +T →T →T ∗F →F → (E ) →x I Can we find an equivalent grammar that can be top-down parsed? I How? 236 , Grading Exercise 7 Extend your compiler project to generate a basic C programm I Finish the basic nanoLang compiler I Your program should produce a correct C program that compiles and implements the nanoLang semantics I A testprogram (“testprog3.nano”) is on the web site. I Bonus: Implement full string functionality (including automatic memory management and garbage collection) 237 , Feedback round I I What was the best part of todays lecture? What part of todays lecture has the most potential for improvement? I Optional: how would you improve it? 238 , Goals for Today I Training exam I Solution discussion 239 , Review: Goals for Today I Training exam I Solution discussion 240 , Feedback round I What was the best part of the course? I Suggestions for improvements? 241 ,