EE-166 Super Buffer and Schmitt Trigger David W. Parent SJSU

Transcription

EE-166 Super Buffer and Schmitt Trigger David W. Parent SJSU
EE-166 Super Buffer and Schmitt
Trigger
David W. Parent
SJSU
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Super Buffer
• We know that to drive large loads we
increase the widths of our transistors.
• How do we drive these larger transistors?
– Scale a chain of inverters.
Cd
α (lnα −1) =
Cg
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Super Buffer
• How do we know how many to use in the chain
and how to we scale up?
• If the Drain Capacitance is close to zero, the
scaling factor reduces to e=2.718.
• What do we do when it is not?
– Solve numerically for α.
Cd
α (lnα −1) =
Cg
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Super Buffer
• Rearrange the design equation.
A=
Cd
+α
Cg
α
• Repeat until the equations
converge to 2 decimal
places.
α = eA
Make a guess for α
Calculate A, Plug A
into the second equation.
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Design flow of a Super Buffer
• Use the equivalent inverter technique to design symmetric
propagation delays of the the logic gate you need to buffer
• Calculate the capacitive load the circuit needs to drive
(This may be given to you.)
• Find α or calculate or if the situation warrants it use α=3.
• Calculate the number of stages
– Add an extra inverter to the beginning of the chain if the output needs to
be inverted (depending upon an odd or even number of stages.
• Scale each buffer stage by α.
• Calculate power and area
– Does this make sense? if ok then enter into schematic capture and follow
the rest of the design flow.
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Example
• You have a NAND3 that needs to drive a 1000
identical NAND3s with a minimum propagation
delay.
– The output of the buffer should not logically invert the
out put of the NAND3.
– Assume that WP=1.5µm and WN=1.8µm and that Ln
and Lp are minimum sized and that the propagation
delays for the worst case transitions are symmetric for
the NAND3.
– Assume that this will give you symmetric rise and fall
times.
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Find the equivalent inverter of the
NAND3
• In the worst case only 1 PMOS conducts for
charging and all nmos have to turn on to
discharge and that the input that is
controlling the state is closest to ground
– In this example WN and WP are given and we
assume that they already have symmetric
propagation delays.
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Calculate the load you need to
drive
• Find the input capacitance of the NAND2
• Multiply by 1000.
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Find the scaling factor α
Find the COUT of the NAND3
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Find the scaling factor α
Numerically solve for α
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Find the number of stages
In order to be non inverting
we need an extra inverter
at the beginning.
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Calculate WN and WP
Remember we scaled WN by 3
to take into account Leff=3LN.
We divide by 3 to get a regular
inverter.
Ignore the 0.
Are these widths acceptable?
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Calculate the load for each stage
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Calculate the delay for each stage
and the total delay.
Is this delay acceptable?
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Check the power
Is this power acceptable?
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Continue with normal design
flow. • If the circuit is
acceptable
then we
proceed.
Use calculated
capacitance.
1000 NAND3’s
would take a long
time to simulate.
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Schematic
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Results
• The propagation delays were ~1ns with 4%
difference.
– This was 14% slower than we predicted.
Should we adjust the A constant by 1.14?
• If we do then the error between our hand
calculations and our spice results drops to 2%.
• The rise and fall times were ~600ps with
10% difference.
• The power consumption was ~60mW.
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Layout
• This is tricky because we are going from
something that is small to something that is
large.
– Keep the cell height the same as the smallest
inverter and use multipliers
– This will cause the last buffer to have at least 6*6=36
fingers which will lead to a long poly line
OUTPUT
Cell
Height
INPUT
Width changes by αn
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Layout Continued
• Keep the same cell height but
break up the last inverter into
manageable chunks chunks
INPUT
OUTPUT
Try dividing it up into three.
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This causes
the in and out
ports to be on
the same side.
(Maybe you
want this.)
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More options for layout
Ever played Tretris?
INPUT
OUTPUT
OUTPUT
INPUT
Maybe harder to fill.
Hard to fill blank space.
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Lets pick a floor plan and go!
INPUT
OUTPUT
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Design the first inverter
Leave extra room to expand NMOS and PMOS
widths.
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Stamp down a copy and wire.
There is some wasted space,
but lets fix it later.
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Now we make the next inverter
in the buffer
We need an integer number of fingers
but our scaling factor is 6.24.
We come up with a new width that
gives us the closest to 6 fingers.
In this case WP is 10.05µm, and WN
=4.05µm.
See why we left extra space between
the power rails!
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Now the final layout
The final
buffer was
split into 2
instead of
three because
it gave an even
number of
fingers.
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Extract/LVS
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Now the final layout
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The final
buffer was
split into 2
instead of
three
because
it gave an
even
number of
fingers.
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Let’s tighten up the layout
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Final thoughts
• Are the poly lines too long?
– Antenna rules
• Are lines wide enough?
• What would the power be if we had 40
output pins switching at the same time?
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Results (extracted)
• The propagation delays were ~1ns with 3%
difference.
• The rise time was 509ps and the fall time
was ~600ps (14% difference.)
• The power consumption was ~53mW.
• The total area was 53 by 72 µm.
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EE167 Super Buffer For Driving
Output Pins.
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CMOS Schmitt Trigger
• Cleans up slow rising/falling noisy signals.
– Hysteresis
VID
VIU
VIU
VID
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CMOS Schmitt Trigger
2
 VHLTRIP − VTN  W NI
W NF := LNF⋅ 
 ⋅L
VDD − VHLTRIP

 NI
2
Slow Rising Noisy Signals
(Like on an Input Pin)_
 VDD + VTP − VLHTRIP W PI
W PF := LPF⋅ 
 ⋅L
VLHTRIP

 PI
VID
VIU
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Alternate Implementation
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CMOS Schmitt Trigger
Design a Schmitt Trigger to have trip voltages of 1 and 3, that can
drive a 100fF Load at a propagation delay of .5ns.
I tried to use the equations but they were really off. I had to use a
parametric analysis to find WNI and WPI. WNF and WPF were
set from equation. Once the timing was right, I adjusted WNF and
WPF to get the trip voltages right. This of course altered the
timing, but I was closer. The equations were useful as a starting
and helped me understand weather to increase or decrease the
width of a transistor.
The total time to test get a working schematic was 3 hours. It will
probably take another three to get it to LVS and post extraction
simulation. (Note: It took 1.5 hours)
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Final Schematic
Propagation Delay was .49ns
VTRIPHL=.976V 2% Error
VTRIPLH=3.13V 4% Error
WNI
WPI
8.5
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WNF
22.1
WPF
8.78
133.8
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VTRIPLH
Analysis
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VTRIPHL
Analysis
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LAYOUT
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Results from Post Extraction
Simulation
Propagation Delay was .45ns 10%
VTRIPHL=.981V 2% Error
VTRIPLH=2.0V 4% Error
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